| Literature DB >> 34546101 |
Jennifer S Avena1,2, Betsy B McIntosh1,2, Oscar N Whitney1, Ashton Wiens3, Jennifer K Knight1.
Abstract
Problem solving is a critical skill in many disciplines but is often a challenge for students to learn. To examine the processes both students and experts undertake to solve constructed-response problems in genetics, we collected the written step-by-step procedures individuals used to solve problems in four different content areas. We developed a set of codes to describe each cognitive and metacognitive process and then used these codes to describe more than 1800 student and 149 expert answers. We found that students used some processes differently depending on the content of the question, but reasoning was consistently predictive of successful problem solving across all content areas. We also confirmed previous findings that the metacognitive processes of planning and checking were more common in expert answers than student answers. We provide suggestions for instructors on how to highlight key procedures based on each specific genetics content area that can help students learn the skill of problem solving.Entities:
Mesh:
Year: 2021 PMID: 34546101 PMCID: PMC8715770 DOI: 10.1187/cbe.21-01-0016
Source DB: PubMed Journal: CBE Life Sci Educ ISSN: 1931-7913 Impact factor: 3.325
FIGURE 1.Sample problem for students from the Gel/Pedigree content area. Problems in each content area contain a written prompt and an illustrated image, as shown in this example.
Problem-solving process (PsP): Code categories, definitions, and examplesa
| Strategy category | Individual process codes | Description | Example |
|---|---|---|---|
| Orientation | Notice | Identifying components in the question stem. | “I’m underlining that this is autosomal recessive.” |
| Identify Similarity | Noticing similarity between problems. | “This is like the last problem.” | |
| Identify Concept | Explicitly describing the type of problem. | “This is a meiosis problem.” | |
| Recall | Remembering a fact or definition without direct application to the problem. | “Nondisjunction in meiosis 1 yields two different alleles in one gamete.” | |
| Metacognition | Plan | Outlining next steps. | “First, I need to figure out who the disease carriers are, determine the probabilities that they are affected, and then use the product law to determine the likelihood the child will be affected.” |
| Check | Checking solution steps and/or final answer. | “I had to go back and make sure I understood what I need to answer this question correctly.” | |
| Assess Difficulty | Expressing perceived difficulty or unfamiliarity. | “This is a difficult problem and I’m not sure how to get started.” | |
| Execution | Use Information | Applying a single piece of information related to the problem. | “Individual A has a band that migrated slower than Individual B’s band.” |
| Integrate | Linking visual representations with other information | “Looking at the gel and table together, I notice that Lily and Max are both affected, even though Lily has 2 copies of the disease gene and Max has only 1 copy.” | |
| Draw | Drawing or visualizing problem components. | “I’m drawing a Punnett Square in my head.” | |
| Calculate | Using any mathematical statement. | “Together, there is a ⅔ chance that both parents are heterozygous since 1 × ⅔ is ⅔.” | |
| Reasoning | Reason | Providing a logical explanation for a preliminary or final conclusion. | “I determined that II-6 has a 100% chance of being a carrier, because II-6 is not affected, but has a mother that is affected.” |
| Conclusion | Eliminate | Ruling out a final answer. | “It couldn’t be X-linked dominant.” |
| Claim | Providing an answer statement. | “There is a ⅔ chance that the child will be affected.” | |
| Error | Misinterpret | Misunderstanding the question stem. | “The problem was asking for the band that causes the disease.” [Question was asking for the mode of inheritance] |
| General | Clarify | Clarifying the question stem and problem. | “I identified what the question was asking.” |
| State the Process | Stating an action abstractly (no details). | “I am determining the genotypes.” | |
| Restate | Restating a previously stated process |
Examples of student responses are to a variety of content areas and have been edited for clarity. Each individual process code captures the student’s description, regardless of whether the statement is correct or incorrect.
Examples of expert and student documented problem solving on a Gel/Pedigree problem with associated process codesa
| Expert answer: Eliot | Process |
|---|---|
| The question states that the mutation is a deletion in a single gene. | Clarify |
| We don’t know yet if one copy of the mutation can cause the disease. | Use Information |
| We have a gel to look at and a pedigree, so there’s lots of information, and I can use both to make sure I have the inheritance right. | Plan |
| I look at the pedigree and think it looks like a dominant disease because of the inheritance pattern. | Claim and Reason |
| Actually, it has to be dominant, just from the pedigree, because otherwise Zach could not be unaffected. | Claim and Reason |
| I need the gel to decide if it’s X linked or autosomal. | Plan |
| The gel shows two alleles for just about everyone, so that almost answers the question right off the bat—the smaller allele is the mutant allele, and Rose, Jon and Max all have one copy of this allele and one copy of the normal, larger allele, and they have the disease. | Integrate |
| Sounds like autosomal dominant to me. | Claim |
| To be sure I check out just the males in the pedigree— | Check |
| Zach has only normal allele copies and all the other males have two different alleles. | Use Information |
| Thus, the disease cannot be caused by a gene on the X chromosome; since males only have one copy of the X, they would only have one allele. | Eliminate and Reason |
| It must be autosomal dominant. | Claim |
The responses above are all solutions to the question in Figure 1.
Examples of correct student documented problem solving with associated process codes for each content areaa
| Correct student answer: Li for Probability (Wilson’s disease question) | Process |
|---|---|
| We must initially conclude that Hillary and Justin’s parents are carriers for the disease, because they both have children who are affected. | Use Information and Reason |
| However, neither Hillary nor Justin has the disease, so they must not be recessive for it (dd). | Use Information and Reason |
| Both parents of H and J must be Dd, otherwise all or none of the children would have the disease. | Use Information and Reason |
| Chance of Hillary/Justin being Dd is 2/3. Chance being DD is 1/3. | Use Information |
| If Hillary and Justin are Dd, then their child has a 1/4 chance of being diseased. | Use Information |
| So, using the multiplication rule, the child has a 2/3*2/3*1/4 chance of being diseased, which is 1/9. | Reason and Calculate and Claim |
Responses edited slightly for clarity. See Table 2 for a correct student documented solution to the Gel/Pedigree problem.
Comparison of students’ and experts’ process use across all four content areasa
| Prevalence of process (% of answers) | Predicted probability (%) from GLMM | GLMM | |||||||
|---|---|---|---|---|---|---|---|---|---|
| Process | Incorrect student | Correct student | Correct expert | Incorrect student (i) | Correct student (c) | Correct expert (e) | i–c | i–e | c–e |
|
| |||||||||
| Notice | 29.69 | 32.28 | 32.21 | 26.29 | 22.08 | 23.52 | ns | ns | ns |
| Identify Similarity | 3.64 | 5.31 | 0.67 | 0.52 | 0.83 | 0.11 | ns | ns | ns |
| Identify Concept | 3.64 | 4.59 | 20.13 | 0.08 | 0.09 | 1.39 | ns | ** | ** |
| Recall | 24.16 | 28.42 | 45.64 | 21.40 | 22.19 | 44.77 | ns | *** | *** |
|
| |||||||||
| Plan | 18.62 | 25.81 | 51.68 | 15.43 | 17.28 | 53.49 | ns | *** | *** |
| Check | 6.34 | 10.43 | 47.65 | 2.50 | 4.06 | 46.23 | ns | *** | *** |
| Assess Difficulty | 7.29 | 4.41 | 14.09 | 1.55 | 0.83 | 4.29 | * | ns | ** |
|
| |||||||||
| Use Information | 70.85 | 70.41 | 91.28 | 75.53 | 71.39 | 93.28 | ns | *** | *** |
| Integrate | 16.46 | 23.47 | 30.20 | 13.30 | 19.40 | 27.33 | ** | ** | ns |
| Draw | 20.38 | 16.28 | 24.83 | 10.83 | 7.61 | 16.49 | ns | ns | ns |
| Calculate | 44.13 | 40.65 | 41.61 | 45.93 | 38.66 | 40.40 | * | ns | ns |
|
| |||||||||
| Reason | 82.05 | 92.36 | 93.29 | 91.80 | 96.68 | 97.40 | *** | * | ns |
|
| |||||||||
| Eliminate | 4.45 | 12.86 | 16.78 | 2.85 | 8.56 | 12.72 | *** | *** | ns |
| Claim | 97.44 | 98.38 | 96.64 | 99.96 | 99.97 | 99.94 | ns | ns | ns |
|
| |||||||||
| Misinterpret | 2.29 | 0.18 | 0.67 | 0.02 | 0.00 | 0.01 | NA | NA | NA |
|
| |||||||||
| Clarify | 37.79 | 50.99 | 73.83 | 17.80 | 39.74 | 99.06 | *** | *** | ns |
| State the Process | 5.80 | 3.42 | 14.09 | 0.55 | 0.35 | 2.22 | ns | ns | ** |
| Restate | 3.91 | 4.95 | 4.03 | 2.81 | 3.56 | 2.91 | ns | ns | ns |
| 741 | 1112 | 149 | |||||||
Pairwise comparison: incorrect students to correct students (i–c), incorrect students to correct experts (i–e), correct students to correct experts (c–e). NA, no comparison made due to predicted probability of 0 in at least one group. ***p < 0.001; **p < 0.01; *p < 0.05; ns: p > 0.05. See Supplemental Table S1 for standard error of coefficient estimates. Interpretation example: 82.05% and 92.36% of incorrect and correct student answers, respectively, contained Reason. The GLMM, after accounting for individual variability, predicts the probability of an incorrect student using Reason to be 91.80%, while the probability of a correct student using Reason is 96.68%.
Likelihood of processes in student answers varies by content areaa
| Prevalence of process (% of correct and incorrect student answers) | Predicted probability (%) from GLMM | GLMM | ||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Process | Probability | Recombination | Nondisjunction | Gel/Pedigree | Probability (P) | Recombination (R) | Nondisjunction (N) | Gel/ Pedigree (G) | P–R | P–N | P–G | R–N | R–G | N–G |
|
| ||||||||||||||
| Notice | 36.32 | 32.89 | 26.22 | 29.02 | 33.21 | 25.87 | 17.77 | 18.46 | ns | *** | *** | * | ns | ns |
| Recall | 26.15 | 43.41 | 20.65 | 9.27 | 18.35 | 40.29 | 14.15 | 5.07 | *** | ns | *** | *** | *** | *** |
|
| ||||||||||||||
| Plan | 32.20 | 17.70 | 20.42 | 23.90 | 28.24 | 11.28 | 11.44 | 16.71 | *** | *** | ** | ns | ns | ns |
| Check | 5.81 | 5.51 | 11.83 | 13.41 | 2.12 | 1.83 | 4.38 | 6.5 | ns | ns | ** | ** | *** | ns |
| Assess Difficulty | 4.36 | 5.01 | 7.66 | 5.37 | 1.06 | 1.04 | 1.71 | 1.29 | ns | ns | ns | ns | ns | ns |
|
| ||||||||||||||
| Use Information | 93.70 | 82.30 | 36.66 | 65.85 | 96.25 | 86.75 | 31.46 | 69.53 | *** | *** | *** | *** | *** | *** |
| Integrate | 20.82 | 8.35 | 14.39 | 45.12 | 17.82 | 5.67 | 9.47 | 43.53 | *** | ** | *** | ns | *** | *** |
| Draw | 22.76 | 13.19 | 28.77 | 8.54 | 13.65 | 4.08 | 15.36 | 2.64 | *** | ns | *** | *** | ns | *** |
| Calculate | 77.97 | 76.13 | 0.00 | 0.24 | NA | NA | NA | NA | NA | NA | NA | NA | NA | NA |
| Reason | 94.43 | 84.98 | 84.69 | 90.49 | 97.52 | 94.10 | 92.88 | 96.93 | * | ** | ns | ns | * | ** |
|
| ||||||||||||||
| Eliminate | 0.48 | 0.00 | 10.44 | 31.46 | NA | NA | NA | NA | NA | NA | NA | NA | NA | NA |
| 413 | 599 | 431 | 410 | |||||||||||
All student answers (correct and incorrect) are reported. Processes excluded from analyses include Claim, those within the Error and General strategies, processes that were present in 5% or fewer of both incorrect and correct student answers. Pairwise comparisons between: Probability (P), Recombination (R), Nondisjunction (N), and Gel/Pedigree (G). NA: no comparison made due to prevalence of 0% in at least one group. ***p < 0.001; **p < 0.01; *p < 0.05; ns: p > 0.05. See Supplemental Table S2 for standard errors of coefficient estimates. Interpretation example: In Probability questions, 94.43% of answers contain Reason, while in Nondisjunction, 84.69% of answers contain Reason. Based on GLMM estimates to account for individual variability in process use, a question in the Probability content area had a 97.52% chance of using Reason, and a question in the Nondisjunction content area had an 92.88% chance of using this process.
Prevalence of processes in correct and incorrect student answers by content areaa
| Prevalence of process (% of correct and incorrect student answers) | ||||||||
|---|---|---|---|---|---|---|---|---|
| Probability | Recombination | Nondisjunction | Gel/Pedigree | |||||
| Process | Incorrect student | Correct student | Incorrect student | Correct student | Incorrect student | Correct student | Incorrect student | Correct student |
|
| ||||||||
| Notice | 32.81 | 39.37 | 31.21 | 34.94 | 24.07 | 26.93 | 25.22 | 30.43 |
| Recall | 21.88 | 29.86 | 29.70 | 60.22 | 24.07 | 19.50 | 11.71 | 8.36 |
|
| ||||||||
| Plan | 26.04 | 37.56 | 13.94 | 22.30 | 18.52 | 21.05 | 19.82 | 25.42 |
| Check | 4.17 | 7.24 | 5.15 | 5.95 | 10.19 | 12.38 | 9.91 | 14.72 |
| Assess Difficulty | 5.21 | 3.62 | 6.97 | 2.60 | 11.11 | 6.50 | 8.11 | 4.35 |
|
| ||||||||
| Use Information | 88.54 | 98.19 | 73.94 | 92.57 | 37.96 | 36.22 | 63.06 | 66.89 |
| Integrate | 18.75 | 22.62 | 10.30 | 5.95 | 5.56 | 17.34 | 41.44 | 46.49 |
| Draw | 28.65 | 17.65 | 21.52 | 2.97 | 12.96 | 34.06 | 9.91 | 8.03 |
| Calculate | 58.33 | 95.02 | 65.15 | 89.59 | 0.00 | 0.00 | 0.00 | 0.33 |
|
| ||||||||
| Reason | 90.10 | 98.19 | 79.70 | 91.45 | 75.93 | 87.62 | 81.08 | 93.98 |
|
| ||||||||
| Eliminate | 0.52 | 0.45 | 0.00 | 0.00 | 2.78 | 13.00 | 26.13 | 33.44 |
| 192 | 221 | 330 | 269 | 108 | 323 | 111 | 299 | |
All student answers (correct and incorrect) are reported. Processes excluded from analyses include Claim, those within the Error and General strategies, processes that were present in 5% or fewer of both correct and incorrect student answers.
The combination of processes associated with the probability of a correct student answer varies by content areaa
|
|
Based on a representative GLMM model with a lasso penalty predicting answer correctness with a moderate penalty parameter (lambda = 25). The intercept represents the likelihood of a correct answer in the absence of all processes initially entered into the model: Notice, Plan, Recall, Check, Assess Difficulty, Use Information, Integrate, Draw, Calculate, Reasoning, Eliminate. Shaded rows indicate the inclusion of negative predictors in combination with positive predictors. Probabilities were calculated using the inverse logit of the sum of the combination of log odds coefficient estimates and the intercept from Supplemental Table S3.
Drawing use categorization
| Categories | Description | Example |
|---|---|---|
| Inaccurate drawing | Drawing contains incorrect components or is incorrectly interpreted. | Student draws a Punnett square/cross and identifies the incorrect offspring probability.In the Probability Giraffe question, we know that II-6 is heterozygous, but the student answer here indicates II-6 is 2/3 likely to be heterozygous: “I look at the pedigree and try to decide what the genotypes of the parents are. I do tests crosses for Rrxrr and RR x rr for II-6. I determine that II-7s parents are both Rr since one of their kids is rr, or short necked. So both II-6 and II-7 have a 2/3 chance of being a carrier. Doing a cross for their kid, if both parents are Rr, she will have a 1/4 chance of being short necked. The total probability of the kid being short necked is (2/3)x(2/3)x(1/4), 1/9.” —Incorrect student answer: Ingrid |
| Inappropriate drawing application | The type of drawing used was not appropriate for the concept, | Student draws multiple Punnett squares instead of using the Product Rule to take into account the probability of parent genotypes.In the Probability Dimples problem, we know that Pritya has a 2/3 likelihood of being heterozygous, but the student answer here creates two separate accurate Punnett squares to account for the uncertainty in Pritya’s genotype instead of using genotype probabilities multiplied over multiple generations: “1. read the question and look at the pedigree 2. try to give genotypes to people 2a. Narayan has to be heterozygous because she has to have one recessive allele from her mother but she is not affected with the dimple phenotype, so she has one dominant allele. 2b. Pritya can be either homozygous dominant or heterozygous because her parents were heterozygotes and she has dimples. 3. drew a punnett square of the possible crosses between Pritya and Narayan (Dd x Dd and DD x Dd). 3a. if Pritya is homozygous dominant, the child will have dimples. 3b. if Pritya is heterozygous, the child has a 1/4 chance of not having dimples. 4. final answer: we have to know the genotype of Pritya before making a conclusion on the child, so 1/4 or 0.”—Incorrect student answer: IsabellaStudent draws a Punnett square of unlinked genes for a scenario in which genes are linked.In the Recombination Aldose gene question, the distance between genes (e.g., map units) must be considered, but the student answer here does not account for linked genes: “1. Read through the question 2. Examined the cross 3. Made a punnet square crossing AaFf with aaff 4. Determined that 1/4 or 25% of the offspring are Aaff and that phenotype would only produce aldose, not fructose.” —Incorrect student answer: Ivan |
FIGURE 2.Drawing is commonly inaccurate or inappropriate in incorrect student answers for Probability and Recombination. Drawing categorization from student answers that used Draw and answered incorrectly for content areas of (A) Probability (n = 55) and (B) Recombination (n = 71). Each category is mutually exclusive, so those that have both Inaccurate drawing/Inappropriate drawing are not in the individual use categories. “No drawing error” indicates neither inaccurate nor inappropriate drawings were described. “Cannot determine” indicates not enough information was provided in the students’ written answer to assign a drawing use category.