| Literature DB >> 24376682 |
Katrin Jaun-Frutiger1, Dario Cazzoli2, René M Müri1, Claudio L Bassetti1, Thomas Nyffeler3.
Abstract
In the antisaccade task, subjects are requested to suppress a reflexive saccade towards a visual target and to perform a saccade towards the opposite side. In addition, in order to reproduce an accurate saccadic amplitude, the visual saccade vector (i.e., the distance between a central fixation point and the peripheral target) must be exactly inverted from one visual hemifield to the other. Results from recent studies using a correlational approach (i.e., fMRI, MEG) suggest that not only the posterior parietal cortex (PPC) but also the frontal eye field (FEF) might play an important role in such a visual vector inversion process. In order to assess whether the FEF contributes to visual vector inversion, we applied an interference approach with continuous theta burst stimulation (cTBS) during a memory-guided antisaccade task. In 10 healthy subjects, one train of cTBS was applied over the right FEF prior to a memory-guided antisaccade task. In comparison to the performance without stimulation or with sham stimulation, cTBS over the right FEF induced a hypometric gain for rightward but not leftward antisaccades. These results obtained with an interference approach confirm that the FEF is also involved in the process of visual vector inversion.Entities:
Mesh:
Year: 2013 PMID: 24376682 PMCID: PMC3869760 DOI: 10.1371/journal.pone.0083297
Source DB: PubMed Journal: PLoS One ISSN: 1932-6203 Impact factor: 3.240
Figure 1Mean gain 1 (error bars: +/− 1 standard error of the mean (SEM)) of antisaccades for the three stimulation conditions (cTBS right FEF; sham right FEF, no stimulation) and the two directions (leftward; rightward).
cTBS over the right FEF induced a significantly hypometric gain for rightward antisaccades, but not for leftward ones (* indicate significant post hoc tests, Bonferroni-corrected; rightward control vs. rightward TBS: p = .011; rightward sham vs. rightward TBS: p = .003; leftward TBS vs. rightward TBS: p = .012).