| Literature DB >> 30258499 |
A Daghighi1, H Tropp2, N Dahlström3, A Klarbring4.
Abstract
BACKGROUND: In scoliosis, kypholordos and wedge properties of the vertebrae should be involved in determining how stress is distributed in the vertebral column. The impact is logically expected to be maximal at the apex. AIM: To introduce an algorithm for constructing artificial geometric models of the vertebral column from DICOM stacks, with the ultimate aim to obtain a formalized way to create simplistic models, which enhance and focus on wedge properties and relative tilting. MATERIAL/Entities:
Keywords: Comsol model; FEM Stress-Investigation; Mechanical loading; Pathological mechanisms; Scoliosis; Thoracal Idiopathic
Year: 2018 PMID: 30258499 PMCID: PMC6128020 DOI: 10.2174/1874120701812010051
Source DB: PubMed Journal: Open Biomed Eng J ISSN: 1874-1207
Patient specifications. The sacrum to table angle is written as positive if the sacrum line when view from above along the z-axis, is rotated clockwise. All patients have primary right-convex thorakal cobb-curve, i.e. the curvature in the coronal plane is right convex. The age is that at pre-op CT.
| Patient | Convexity | Diagnosis subtype | Apex level | Cobb angle | Apex rotation | Sacrum to table angle | Age |
|---|---|---|---|---|---|---|---|
| 1 | Right-convex | Idiopathic | T9 | 47 | 33 | -1.5 | 17 |
| 2 | Right-convex | Idiopathic | T7 | 46 | 9.7 | 7.3 | 18 |
| 3 | Right-convex | Idiopathic | T10 | 82 | 49.9 | 0.4 | 15 |
| 4 | Right-convex | Idiopathic | T8 | 50 | 22.9 | 2.1 | 16 |
| 5 | Right-convex | Idiopathic | T9 | 18 | 40.5 | 2.7 | 14 |
Correlation coefficients between the apex rotation and apex top response angles for the 5 basic load-states.
| Load state | 1 | 2 | 3 | 4 | 5 |
| Corr.coeficcient | 0.79 | 0.95 | 0.67 | 0.11 | 0.49 |
Statistical pairwise t-tests for difference in apex top response angle, for variations of the models using the basic 5 load-states. Based upon the mean of the variable obtained by subtracting the stochastic variable corresponding to the first type of model, from that corresponding to the second type of model (the Matlab built-in function ’ttest’ was used).
| Isotropic models, basic states | n=25, p-value ≈ 0.73 |
| Isotropic, basic states | n=25, p-value ≈ 0.79 |
| Isotropic, with additional counterclockwise | n=25, p-value ≈ 0.97 |
| Isotropic | n=25, p-value ≈ 0.084 |
Comparison of meshing times for the apex in three different models.
| – | Lower Vertebra | Apex | Upper Vertebra |
|---|---|---|---|
| Harmonically smoothed model | 38 sec | 25 sec | 13 sec |
| Manually segmented model | 39 sec | 37 sec | 15 sec |
| Artificial geometric model | <0.5 sec | <0.5 sec | <0.5 sec |
Comparison of calculation times for test runs on the apex in three different models, using isotropic parameters and ortotropic parameters respectively. Due to a shortage of RAM in our equipment, the test-runs for the manually segmented model were made with a mesh of type coarser, whereas the others used type coarse. Each of the values was reproduced ±2 second three consecutive times.
| – | Orthotropic | Isotropic |
|---|---|---|
| Harmonically smoothed model | 31 sec | 30 sec |
| Manually segmented model | 49 sec | 49 sec |
| Artificial geometric model | 5 sec | 5 sec |
Some material constant approximations based upon Kurutz [18], Schmidt et al. [24] and the references therein. Y denotes the (determining elements of the matrix of) Young modulus (elastic moduli) in MPa, and v the Poisson ratio.
| Y=3500, ν=0.25, Density1≈1908 kg/m3 | |
| Y≈252, ν≈0.47, Density3≈1120 kg/m3 |
1Built-in approximation, see main text. 2 Based upon Kurutz [18] p.219-223, elastic fiber approximation (Y = 500,ν= 0.45) and fluid-like solid for nucleus pulposus (Y = 4, ν = 0.50), mean value was used. 3Approximated as 60% water and 40% collagen, see main text.
Voigt map to the index pairs (i,j) and (n,m)s
| η(ij)=1 | η(ij)=2 | η(ij)=3 | η(ij)=4 | η(ij)=5 | η(ij)=6 | |
|---|---|---|---|---|---|---|
| η(ij)=1 | 1 | 0 | 0 | 0 | 0 | 0 |
| η(ij)=2 | 0 | 1 | 0 | 0 | 0 | 0 |
| η(ij)=3 | 0 | 0 | 1 | 0 | 0 | 0 |
| η(ij)=4 | 0 | 0 | 0 | ½ | 0 | 0 |
| η(ij)=5 | 0 | 0 | 0 | 0 | ½ | 0 |
| η(ij)=6 | 0 | 0 | 0 | 0 | 0 | ½ |