| Literature DB >> 20637098 |
Emmanuelle Revardel1, Alain Franc, Rémy J Petit.
Abstract
BACKGROUND: In heterogeneous environments, sex-biased dispersal could lead to environmental adaptive parental effects, with offspring selected to perform in the same way as the parent dispersing least, because this parent is more likely to be locally adapted. We investigate this hypothesis by simulating varying levels of sex-biased dispersal in a patchy environment. The relative advantage of a strategy involving pure maternal (or paternal) inheritance is then compared with a strategy involving classical biparental inheritance in plants and in animals.Entities:
Mesh:
Year: 2010 PMID: 20637098 PMCID: PMC3055266 DOI: 10.1186/1471-2148-10-217
Source DB: PubMed Journal: BMC Evol Biol ISSN: 1471-2148 Impact factor: 3.260
Figure 1Simulation of dispersal on a checker board. A. The plant model. B. The animal model. The white (0) and grey (1) squares represent environmental heterogeneity. Position of each individual is shown by a cross: F for father, M for mother, O for offspring. Arrows represent how dispersal was modelled. Dispersal is relative to the scale of the environment.
Figure 2The relative advantage of the maternal strategy over the biparental strategy, . Dispersal parameters are relative to the scale of the environment.
Figure 3The relative advantage of the maternal strategy over the biparental strategy, . Dispersal parameters are given relatively to the scale of the environment.
Figure 4Minimum pollen or male dispersal values needed for . For similar seed or female dispersal, much higher male than pollen dispersal values are needed to exert the same selective pressure in favor of maternal effects, illustrating the high propensity of plants to evolve maternal effects.
Derivation of the mean adaptive value of offspring for each of the three strategies of inheritance (biparental, maternal and paternal)
| Environnement1 | Offspring fitness | |||||||
|---|---|---|---|---|---|---|---|---|
| 0/0 | 0/0 | 0/0 | 1 | n1 | p1 | 1 | 1 | 1 |
| 0/1 | 0/1 | 1/0 | 2 | n2 | p2 | α | α | α |
| 0/0 | 1/1 | 0/0 | 3 | n3 | p3 | (1 + α)/2 | α | 1 |
| 0/1 | 1/0 | 1/0 | 4 | n4 | p4 | (1 + α)/2 | 1 | α |
| Total | 20,000 | 1 | wb = p1 + αp2 + (1+ α)(p3 + p4)/2 | wm = p1 + p4 + α(p2 + p3) | wp = p1 + p3 + α(p2+ p4) | |||
1 Values before the slash correspond to the plant model and after the slash to the animal model. In the plant model, the father is always in state 0, in the animal model, the offspring is always in state 0