| Literature DB >> 18788893 |
Stephanie Dellicour1, Feiko O ter Kuile, Andy Stergachis.
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Year: 2008 PMID: 18788893 PMCID: PMC2531138 DOI: 10.1371/journal.pmed.0050187
Source DB: PubMed Journal: PLoS Med ISSN: 1549-1277 Impact factor: 11.069
Figure 1Probability that an Embryo Will Encounter Artemisinins Inadvertently During the Critical Six-Week Period of Its Development (Week Four to Week Ten), According to the Average Number of ACT Treatments Received Per Year
In the figure, χ = number of treatments per year, t = embryo-sensitive period in days (set as 42 days or six weeks), and p = period of treatment and persistence of drug (set as three days because ACTs are normally deployed as a three-day regimen and artemisinins are eliminated within hours after each dose). The inadvertently exposed group will consist of women taking ACTs for confirmed malaria and for presumed malaria. It has been estimated that over 70% of malaria episodes in rural Africa and about 50% in urban areas are self-treated without consulting trained professionals [39]. Thus, many of these will be presumptive treatments without involvement of the formal health services, diagnostic confirmation of malaria, or screening for potential pregnancy. Even if more women seek treatment at health facilities with the deployment of more expensive ACTs and rapid diagnostic tests, antimalarials are often administered disregarding any diagnostic test. Studies in Africa indicated that between 30% and 50% of patients with a negative diagnostic test (microscopy or rapid diagnostic test) were still prescribed antimalarial drugs [40,41]. These proportions are likely to increase further when successful malaria control reduces malaria exposure. (Adapted from [16].)
Figure 2Sample Size Calculation for Pregnancy Exposure Registry by Defect Frequency and Detectable Difference
Exposed to comparison group ratio = 1:1, power = 80%, and one-sided a = 0.05. Based on the formula for cohort design described in Strom's Pharmacoepidemiology [25]: N = 1/[p(1 - R)]2 × [Z1-a√((1 + 1/k)U(1 − U)) + Z1-ß√(pR(1 - Rp) + (P(1 - P))/k)] 2 where p is the incidence of disease in unexposed; R is the minimum relative risk to detect; k is the ratio of unexposed controls to exposed, and U = (Kp + pR)/(k + 1).