| Literature DB >> 29581799 |
Xuanqian Xie1,2, Chenglin Ye3, Nicholas Mitsakakis4,5.
Abstract
BACKGROUND: We designed a simulation study to assess how the conclusions of a non-inferiority trial (NIT) will change if the observed risk is different from the expected risk.Entities:
Keywords: Hazard ratio; Non-inferiority trial; Simulation study; Time-to-event data; Underlying risk
Year: 2018 PMID: 29581799 PMCID: PMC5862084 DOI: 10.14740/jocmr3349e
Source DB: PubMed Journal: J Clin Med Res ISSN: 1918-3003
Figure 1Illustrative example of the simulation.
Figure 2Upper limit of 95%CI of hazard ratio versus the underlying risk in active control group (true hazard ratio = 1). We randomly selected 1,000 out of 10,000 simulated trials, but the fitted line used the entire data. The horizontal line was an empirical non-inferiority margin, hazard ratio of 1.35.
The Probability of Rejecting the Null Hypothesis Using Hazard Ratio
| Non-inferiority margin | Underlying risk in control group | |||
|---|---|---|---|---|
| < 10% | 10-25% | 25-75% | > 75% | |
| True hazard ratio = 1 | ||||
| HR = 1.2 | 0.067 | 0.152 | 0.323 | 0.513 |
| HR = 1.35 | 0.131 | 0.323 | 0.684 | 0.903 |
| HR = 1.5 | 0.224 | 0.527 | 0.890 | 0.993 |
| True hazard ratio = 0.95 | ||||
| HR = 1.2 | 0.094 | 0.200 | 0.482 | 0.716 |
| HR = 1.35 | 0.194 | 0.413 | 0.790 | 0.968 |
| HR = 1.5 | 0.286 | 0.607 | 0.935 | 0.999 |
| True hazard ratio = 1.05 | ||||
| HR = 1.2 | 0.056 | 0.112 | 0.198 | 0.305 |
| HR = 1.35 | 0.104 | 0.252 | 0.544 | 0.771 |
| HR = 1.5 | 0.171 | 0.425 | 0.821 | 0.970 |
The probability of rejecting the null hypothesis is the same as the statistical power in our simulations.
Figure 3The upper limit of difference in two Kaplan-Meier estimators versus follow up time (true hazard ratio = 1). We randomly selected 1,000 out of 10,000 simulated trials in this plot, but the fitted line used the entire data. The horizontal line was an empirical non-inferiority margin, representing the difference in two Kaplan-Meier estimators of 10%.
The Probability of Rejecting The Null Hypothesis Using the Difference in Two Kaplan-Meier Estimators
| Non-inferiority margin | Underlying risk in control group | |||
|---|---|---|---|---|
| < 10% | 10-25% | 25-75% | > 75% | |
| True hazard ratio = 1 | ||||
| DTKME = 2.5% | 0.221 | 0.117 | 0.077 | 0.123 |
| DTKME = 5% | 0.656 | 0.334 | 0.199 | 0.352 |
| DTKME = 10% | 0.981 | 0.831 | 0.607 | 0.842 |
| DTKME = 15% | 1.000 | 0.990 | 0.922 | 0.984 |
| True hazard ratio = 0.95 | ||||
| DTKME = 2.5% | 0.275 | 0.154 | 0.151 | 0.229 |
| DTKME = 5% | 0.699 | 0.400 | 0.319 | 0.502 |
| DTKME = 10% | 0.995 | 0.885 | 0.750 | 0.920 |
| DTKME = 15% | 1.000 | 0.993 | 0.960 | 1.000 |
| True hazard ratio = 1.05 | ||||
| DTKME = 2.5% | 0.190 | 0.086 | 0.039 | 0.058 |
| DTKME = 5% | 0.551 | 0.257 | 0.120 | 0.228 |
| DTKME = 10% | 0.977 | 0.750 | 0.468 | 0.735 |
| DTKME = 15% | 1.000 | 0.977 | 0.858 | 0.972 |
DTKME: difference in two Kaplan-Meier estimators at follow-up of 5 years. The probability of rejecting the null hypothesis is the same as the statistical power in our simulations.