| Literature DB >> 27587712 |
Abstract
A class of steady-state compartmental models of the circulation is examined and it is shown that the mathematical problem for this model class involves a single nonlinear equation. In an important subclass and with certain assumptions regarding the form of the Starling-type cardiac function curves, the single equation is of the form Z = μ + λ log[(1 - Z)/Z] where μ and λ are mathematical parameters related to the physiological parameters of the system and Z is proportional to the cardiac output. This result holds regardless of the number and arrangement of compartments within the model itself or of the number of physiological parameters the model contains. An example of this class with 25 physiological parameters is presented to illustrate this approach.Entities:
Keywords: cardiovascular system; closed circulation; intrathoracic pressure; steady‐state compartmental model
Mesh:
Year: 2016 PMID: 27587712 PMCID: PMC5027352 DOI: 10.14814/phy2.12945
Source DB: PubMed Journal: Physiol Rep ISSN: 2051-817X
Figure 1(A) The normal steady state of the five‐compartment model of the circulation with chest and abdominal cavities, as described in the text. (See Table 2.) The units for the variables shown in these figures are: flow – L/min, pressure – mmHg, volume – L. (B) Three‐dimensional graphical analysis of the normal model steady state showing intersection of the right and left heart Starling curves and the conservation plane. (C) Two‐dimensional graphical analysis of the normal model steady state showing the intersection of the right heart Starling curve and the composite flow (“venous return”) curve.
Normal values assumed for the parameters used in the five‐compartment circulatory model. The cardiac function curve parameters were taken from (White et al. 1983), the intrathoracic and abdominal pressures were taken from (Agostoni and Rahn 1960), and the remaining parameters were taken from (Coleman et al. 1974)
| Parameter type | Parameter | Value |
|---|---|---|
| Volume (L) | BV – blood volume | 5.000 |
|
| 0.452 | |
|
| 0.102 | |
|
| 0.290 | |
|
| 0.102 | |
|
| 1.380 | |
|
| 0.600 | |
| Compliance (L/mmHg) | C1 – compliance of the right atrium | 0.012 |
| C2 – compliance of the lungs | 0.015 | |
| C3 – compliance of the left atrium | 0.012 | |
| C4 – compliance of the viscera | 0.130 | |
| C5 – compliance of the periphery | 0.040 | |
| Resistance (mmHg/L/min) | RA2 – arterial resistance of the lungs | 0.6 |
| RV2 – venous resistance of the lungs | 1.2 | |
| RA4 – arterial resistance of the viscera | 36.8 | |
| RV4 – venous resistance of the viscera | 3.2 | |
| RA5 – arterial resistance of the periphery | 38.4 | |
| RV5 – venous resistance of the periphery | 1.6 | |
| External pressure (mmHg) |
| −4 |
|
| −4 | |
| Cardiac parameters |
| 13.5 |
|
| 55.2 | |
|
| 0.870 | |
|
| 23.1 | |
|
| 0.326 |
Steady‐state values of the physiological variables in the five‐compartment model of the circulation. Units used: flow – L/min, pressure – mmHg, volume – L, resistance – mmHg/L/min. All pressures are measured relative to normal atmospheric pressure (760 mmHg)
| Variable | Name | Equation | Normal value | Case 1 resistance changes | Case 2 external pressure changes |
|---|---|---|---|---|---|
|
| Mu | See equation | 0.326 | 0.536 | 0.372 |
|
| Lambda |
| 0.0838 | 0.138 | 0.0838 |
|
| Scaled cardiac output |
| 0.370 | 0.523 | 0.404 |
|
| Cardiac output | KZ | 5 | 7.1 | 5.5 |
|
| Right atrial pressure (also central venous pressure) |
| 0 | 0.70 | −3.8 |
|
| Pulmonary pressure |
| 10 | 14 | 7 |
|
| Left atrial pressure |
| 4 | 5.9 | 0.4 |
|
| Visceral pressure |
| 8 | 5.5 | 4.9 |
|
| Peripheral pressure |
| 4 | 9.6 | 0.5 |
| PA | Arterial pressure |
| 100 | 116 | 105 |
| PPA | Pulmonary arterial pressure |
| 13 | 19 | 10 |
|
| Right atrial volume |
| 0.15 | 0.16 | 0.15 |
|
| Pulmonary volume |
| 0.50 | 0.56 | 0.52 |
|
| Left atrial volume |
| 0.20 | 0.22 | 0.20 |
|
| Visceral volume |
| 2.94 | 2.62 | 3.06 |
|
| Peripheral volume |
| 0.76 | 0.98 | 0.62 |
| TPR | Total peripheral resistance |
| 20 | 16 | 20 |
|
| Fraction visceral flow |
| 0.50 | 0.21 | 0.50 |
|
| Fraction peripheral flow | 1 − | 0.50 | 0.79 | 0.50 |
Figure 2(A) The steady state of the five‐compartment model of the circulation with the peripheral arterial resistance reduced by 50% and the visceral arterial resistance doubled from the normal values. (See Case 1 in Table 2.) (B) Three‐dimensional graphical analysis of the model steady state with the peripheral arterial resistance reduced by 50% and the visceral arterial resistance doubled from the normal values. In this figure showing the intersection of the right and left Starling curves and the conservation plane, only the conservation plane has shifted from Figure 1B. (C) Two‐dimensional graphical analysis of the model steady state with the peripheral arterial resistance reduced by 50% and the visceral arterial resistance doubled from the normal values. In this figure showing the intersection of the right heart Starling curve and the composite flow (“venous return”) curve, only the latter has shifted from Figure 1C.
Figure 3(A) The steady state of the five‐compartment model of the circulation with both the intrathoracic and abdominal pressures decreased from −4 to −8 mmHg. (See Case 2 in Table 2.) (B) Three‐dimensional graphical analysis of the model steady state with both the intrathoracic and abdominal pressures decreased from −4 to −8 mmHg. In this figure showing the intersection of the right and left Starling curves and the conservation plane, all three curves have shifted from normal. (C) Two‐dimensional graphical analysis of the model steady state with both the intrathoracic and abdominal pressures decreased from −4 to −8 mmHg. In this figure showing the intersection of the right heart Starling curve and the composite flow (“venous return”) curve, both curves have shifted from normal.