| Literature DB >> 27429890 |
Abstract
In this paper, the maximum capacity path problem in time-varying network is presented, where waiting times at vertices are not allowable. Moreover, the capacities are considered the generalized trapezoidal fuzzy number. An exact algorithm is proposed which can find a optimal solution of problem subject to the time of path is at most T, where T is a given time horizon.Entities:
Keywords: Fuzzy numbers; Maximum capacity path; Time-varying network
Year: 2016 PMID: 27429890 PMCID: PMC4932022 DOI: 10.1186/s40064-016-2654-y
Source DB: PubMed Journal: Springerplus ISSN: 2193-1801
Fig. 1Time-varying network G
Transit times and fuzzy capacities for network G
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| 0 | (1, 2, 3, 4; 0.5) | 1 | (2, 3, 4, 5; 0.4) | 1 | (2, 3, 4, 6; 0.3) | 1 | (2, 3, 5, 6; 0.6) | 3 |
| 1 | (2, 3, 4, 5; 0.6) | 1 | (2, 4, 6, 8; 0.3) | 2 | (1, 2, 3, 4; 0.4) | 1 | (1, 3, 5, 6; 0.5) | 2 |
| 2 | (1, 3, 5, 7; 0.5) | 2 | (1, 3, 4, 5; 0.3) | 2 | (2, 3, 5, 7; 0.4) | 2 | (2, 4, 5, 7; 0.7) | 1 |
| 3 | (2, 4, 6, 8; 0.4) | 2 | (2, 3, 4, 6; 0.5) | 1 | (1, 3, 4, 6; 0.4) | 2 | (2, 4, 6, 8; 0.6) | 2 |
| 4 | (1, 2, 3, 4; 0.5) | 3 | (1, 4, 5, 7; 0.6) | 3 | (2, 3, 5, 6; 0.3) | 2 | (3, 4, 5, 7; 0.6) | 2 |
| 5 | (1, 2, 3, 5; 0.6) | 2 | (2, 5, 6, 8; 0.5) | 4 | (3, 4, 5, 6; 0.3) | 3 | (2, 3, 4, 7; 0.5) | 2 |
| 6 | (3, 4, 5, 7; 0.5) | 3 | (1, 3, 5, 7; 0.4) | 3 | (2, 3, 5, 7; 0.5) | 3 | (1, 2, 3, 4; 0.6) | 3 |
Fig. 2A layered time-varying network G for example 2
Calculation of optimal solution for example 1
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| Vertex |
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| Path | Time |
| Path | Time |
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| 1 | P(1) | 0 |
| 7 | P(1–2–5–7) | 6 | (2, 3, 4, 5; 0.2) |
| 2 | P(1–2) | 1 | (5, 6, 7, 8; 0.5) | 8 | P(1–2) | 1 | (5, 6, 7, 8; 0.5) |
| 3 | P(1–3) | 1 | (1, 2, 3, 4; 0.2) | 9 | P(1–2–5–9) | 6 | (5, 6, 7, 8; 0.5) |
| 4 | P(1–2–4) | 3 | (2, 3, 4, 5; 0.2) | 10 | P(1–2–5–8–10) | 10 | (1, 2, 3, 4; 0.7) |
| 5 | P(1–2–5) | 3 | (5, 6, 7, 8; 0.5) | 11 | P(1–2–5–8–11) | 1 | (5, 6, 7, 8; 0.5) |
| 6 | P(1–3–6) | 3 | (1, 2, 3, 4; 0.2) | 12 | P(1–2–5–8–11–12) | 15 | (5, 6, 7, 8; 0.5) |