| Literature DB >> 27422120 |
Jana Votapkova1, Pavlina Zilova2.
Abstract
This paper estimates the effect of the abolition of user charges for children's outpatient care (30 CZK/1.2 EUR) in 2009 on the demand for ambulatory doctor visits in the Czech Republic. Because the reform applied only to children, we can employ the difference-in-differences approach, where children constitute a treatment group and adults serve as a control group. The dataset covers 1841 observations. Aside from the treatment effect, we control for a number of personal characteristics using micro-level data (European Union Statistics on Income and Living Conditions). Using the zero-inflated negative binomial model, we found no significant effect from the abolition of user charges on doctor visits, suggesting either that user charges are ineffective in the Czech environment or that their value was set too low. On the contrary, personal income, the number of household members and gender have a significant effect. A number of robustness checks using restricted samples confirm the results.Entities:
Keywords: Co-payments; Czech Republic; Natural experiment; Outpatient care; Zero-inflated negative binomial model (ZINB)
Year: 2016 PMID: 27422120 PMCID: PMC4947065 DOI: 10.1186/s13561-016-0105-7
Source DB: PubMed Journal: Health Econ Rev ISSN: 2191-1991
Fig. 1Frequency distribution - visits
Summary statistics
| Variable | Mean | Std. Dev. | Min. | Max. | Median |
|---|---|---|---|---|---|
| Female | 0.528 | 0.499 | 0 | 1 | 1 |
| Visits | 3.539 | 4.533 | 0 | 20 | 2 |
| Members | 2.806 | 1.211 | 1 | 7 | 3 |
| Reform | 0.382 | 0.486 | 0 | 1 | 0 |
| Dummy_child | 0.153 | 0.36 | 0 | 1 | 0 |
| Interaction | 0.062 | 0.241 | 0 | 1 | 0 |
| Log_income_memb | 12.002 | 0.494 | 10.375 | 14.271 | 11.948 |
Zero-inflated negative binomial model
| Number of obs = 1841 | ||
|---|---|---|
| Non-zero obs = 1176 | ||
| Zero obs = 665 | ||
| LR | ||
| Prob > | ||
| Visits | Coef. | |
| Count process = neg. binomial | ||
| reform | 0.010 | |
| dummy_child | –0.242 | |
| interaction | –0.497 | |
| female | 0.190*** | |
| members | –0.132*** | |
| log_income_memb | –0.337*** | |
| _cons | 5.840*** | |
| Inflation model = logit | ||
| reform | 1.232*** | |
| dummy_child | 4.377*** | |
| interaction | –0.588 | |
| female | –1.233*** | |
| members | 0.502*** | |
| log_income_memb | 0.261 | |
| _cons | –6.292*** | |
| ln | –0.451 | |
|
| 0.637 | |
Likelihood-ratio test of α = 0: (01) = 1393.26 Pr = 0.0000
Vuong test of zinb vs. standard negative binomial: z = 6.91 Pr >z = 0.0000
Notes: * p<=0.1, ** p<=0.05, *** p<=0.01
In order to interpret coefficients of the log–linear model, exponentiating is necessary; exp(coeff)
Zero-inflated negative binomial model: robustness checks
| (1) | (2) | (3) | (4) | (5) | (6) |
|---|---|---|---|---|---|
| Control group | Adults aged 18 to 26 | Childless adults | Adults without the elderly | Employed adults up to 65 years | |
| Number of obs = 494 | Number of obs = 1243 | Number of obs = 1471 | Number of obs = 1117 | ||
| Non-zero obs = 130 | Non-zero obs = 735 | Non-zero obs = 837 | Non-zero obs = 579 | ||
| Zero obs = 364 | Zero obs = 508 | Zero obs = 634 | Zero obs = 538 | ||
| LR | LR | LR | LR | ||
| Prob > | Prob > | Prob > | Prob > | ||
| Count process | |||||
| reform | –0.249 | –0.015 | 0.034 | 0.109 | |
| dummy_child | 0.172 | –0.023 | –0.072 | 0.133 | |
| interaction | -0.659 | –0.246 | –0.583 | –0.851 | |
| female | –0.116 | 0.144** | 0.368*** | 0.355*** | |
| members | –0.029 | –0.265*** | –0.059* | 0.016 | |
| log_income_memb | –0.158 | –0.461*** | –0.202*** | –0.003 | |
| _cons | 3.142 | 7.608*** | 3.675*** | 0.872 | |
| Logit | |||||
| reform | 0.725 | 0.807*** | 1.617*** | 1.605*** | |
| dummy_child | 3.284*** | 3.415*** | 4.765*** | 5.042*** | |
| interaction | –0.233 | –0.106 | –0.988 | –1.020 | |
| female | –0.967*** | –0.881*** | –1.334*** | –1.462*** | |
| members | 0.414** | 0.660*** | 0.471*** | 0.333** | |
| log_income_memb | 0.299 | 0.246 | 0.115 | 0.122 | |
| _cons | –5.532 | –5.895** | –4.809 | –4.567 | |
| ln | –0.443 | –0.757 | –0.219 | –0.242 | |
|
| 0.642 | 0.469 | 0.804 | 0.785 |
Notes: * p<=0.1, ** p<=0.05, *** p<=0.01
In order to interpret coefficients of the log–linear model, exponentiating is necessary; exp(coeff)