| Literature DB >> 22666021 |
Abstract
Odor detection thresholds (ODTs) are used for assessing outdoor and indoor air quality. They are obtained experimentally by olfactometry and psychophysical methods, and large compilations are available in the literature. A non-linear regression equation was fitted to describe the ODT variability of 114 aliphatic compounds based on the alkyl chain length for different homologous series (carboxylic acids, aldehydes, 2-ketones, esters, 1-alcohols, amines, thiols, thioethers and hydrocarbons). The resulting equation reveals an effect of the functional group, molecular size and also an interaction between both factors. Although the mechanistic interpretation of results is uncertain, the relatively high goodness-of-fit (R(2) = 0.90) suggests that ODT values of aliphatic compounds can be predicted rather accurately, which is not the case for rigid molecules. This equation may serve as a basis for the development of more complex ODT models taking into account diverse structural features of odorants. The variability of power-law exponents was also investigated for the homologous series.Entities:
Keywords: VOC; odorant; olfaction; olfactometry; psychophysics
Year: 2012 PMID: 22666021 PMCID: PMC3355402 DOI: 10.3390/s120404105
Source DB: PubMed Journal: Sensors (Basel) ISSN: 1424-8220 Impact factor: 3.576
Figure 1.Plot of pOL versus n (number of atoms except hydrogens) for 114 aliphatic compounds. Equations in Table 1 have been fitted for each homologous series. Estimated values of pOL and k (coefficients of Equation (4)) are indicated within the graph.
Fitted equations for ODT (data from [16]) and power-law exponents (data from [3]) corresponding to different homologous series (“Num” stands for the number of compounds used in each ODT equation).
| Thiols | 8 | pOL = 9.5 · [1 − exp(− | PLE = 0.36 |
| Amines | 11 | pOL = 9.5 · [1 − exp(− | PLE = 0.39 + 1.15·exp(−0.3 |
| Esters | 26 | pOL = 9.5 · [1 − exp(−0.075 | PLE = 0.36 + 0.33·exp(−0.3 |
| Thioethers | 12 | pOL = 8.5 · [1 − exp(− | PLE = 0.36 |
| Aldehydes | 11 | pOL = 8.5 · [1 − exp(−0.39 | PLE = 0.36 + 0.33·exp(−0.3 |
| Acids | 11 | pOL = 8.5 · [1 − exp(−0.2 | PLE = 0.36 |
| 1-Alcohols | 12 | pOL = 7.7 · [1 − exp(−0.2 | PLE = 0.36 + 0.51·exp(−0.3 |
| 2-Ketones | 9 | pOL = 7.7 · [1 − exp(−0.13 | PLE = 0.39 + 1.15·exp(−0.3 |
| Hydrocarbons | 12 | pOL = 6.0 · [1 − exp(−0.13 | PLE = 0.39 |