| Literature DB >> 36148139 |
Abstract
Phage therapy uses bacterial viruses (bacteriophages) to infect and kill targeted pathogens. Approximately one decade ago, I started publishing on how possibly to improve upon phage therapy experimentation, practice, and reporting. Here, I gather and expand upon some of those suggestions. The issues emphasized are (1) that using ratios of antibacterial agents to bacteria is not how dosing is accomplished in the real world, (2) that it can be helpful to not ignore Poisson distributions as a means of either anticipating or characterizing phage therapy success, and (3) how to calculate a concept of 'inundative phage densities.' Together, these are issues of phage therapy pharmacodynamics, meaning they are ways of thinking about the potential for phage therapy treatments to be efficacious mostly independent of the details of delivery of phages to targeted bacteria. Much emphasis is placed on working with Poisson distributions to better align phage therapy with other antimicrobial treatments. © Stephen T. Abedon 2022; Published by Mary Ann Liebert, Inc.Entities:
Keywords: MOI; bacteriophage therapy; half-life; inundative phage density; multiplicity of infection; pharmacology
Year: 2022 PMID: 36148139 PMCID: PMC9436263 DOI: 10.1089/phage.2022.0019
Source DB: PubMed Journal: Phage (New Rochelle) ISSN: 2641-6530
FIG. 1.A summary of some of the issues that can be associated with use of MOIs, or ratios more generally, to describe dosing for phage therapy. MOI, multiplicity of infection.
Calculating Half-Lives with Respect to Phage Adsorption
| The not-phage-adsorbed half-life of a bacterium can be approximated as 1/ |
| For concentrations (per mL) of 109, 108, 107, 106, 105, 104, or 103, we have mean free times of 24 s (109), 4 min (108), 40 min (107), 7 h (106), 3 days (105), 4 weeks (104), and 9 months (103), respectively (or 17 s, 3 min, 28 min, 5 h, 2 days, 3 weeks, and 6 months, also respectively, for half-lives). Thus, if you have a more or less constant 107 phages per millimeter with phage numbers substantially exceeding bacterial numbers, then half of the co-located, phage-susceptible bacteria will be lost to phage adsorption every half or so hour, again given |
| In short, neither individual phages will adsorb nor individual bacteria will be adsorbed very quickly given concentrations of phages (determining bacterial survival) or of bacteria (determining free phage persistence) in the range of 106/mL or less. As a result, in terms of calculating MOIactual, it really does not matter how many bacteria are present, unless you have somewhat more than 106 bacteria per milliliter adsorbing phages, and even then phage numbers might be boosted via either |
| In addition, if very few bacteria are present, then even a large MOIinput of, say, 1000, might not result in all that rapid loss of bacteria to phage adsorption. For example, starting with 103 bacteria per milliliter will mean that the associated 106 phages/mL (103 bacteria × 1000 phages bacteria−1 = 106 phages) will take about a quarter of a day to reduce bacterial numbers only by about one half. Further, successful virion production by phage infection of only 103 bacteria per milliliter is unlikely to have much of an impact on phage titers across treated environments, though such |
| How rapidly individual bacteria may be adsorbed by phages is, thus, a function especially of what phage titers have been achieved |
MOI, multiplicity of infection.
FIG. 2.Calculating half-lives (in hours) as a function of concentrations. Concentrations are in per milliliter units and would be adsorbable bacteria for phage half-lives or adsorbing phages for bacterial half-lives, assuming in both cases that “lives” (bacteria or free phages) are lost at the point of adsorption. In either case, concentrations of the adsorber (phages for bacterial half-lives) or “adsorbee” (bacteria for phage half-lives) are assumed to remain constant over time, that is, at the values indicated. Shown as well are mean free times ( = 1/kN or 1/kP; dotted line), though as presented these nearly completely coincide with half-lives [ = ln(2)/kN or ln(2)/kP (solid line)]. The adsorption rate constant, k, in any case has been set to 2.5 × 10−9 mL−1 min−1 from Stent.[51]
FIG. 3.The Poisson distribution and its simplification for r = 0. Shown is how the equation p(0) = e− is derived, that is, by substituting r with 0, where anything raised to the 0th power is equal to 1 and 0!, that is, zero factorial, is also equal to 1. Shown as well is how the resulting equation can be rearranged to define n, that is, MOI, and particularly n = MOIactual. This latter equation alternatively can be written as n = ln[1/p(0)]. Most emphasis in this article is on p(0) = e− and the equivalent n = ln[1/p(0)].
Let's Analyze Some Data
| We can better appreciate the benefits of using Poisson distributions when we apply this framework to real data. Let us consider, for example, the dose-response data provided by Chang et al.[ |
| The next step is to calculate the number of bacteria that are expected to still be alive assuming that MOIactual ≈ MOIinput. From e− |
| We can infer from these observations that bacteria were able to replicate |
| As a conclusion, clearly in this case the impact of phages on bacterial numbers, at least after 24 or so hours of treatment, was substantially less than would be predicted assuming Poisson distributions of adsorptions by all treatment phages. The differences, furthermore, I suspect were due to inefficiencies in phage penetration to targeted bacteria after dosing into the murine lung. This, I should mention, is not an argument against the validity of Poisson distributions in describing phage adsorption to bacteria, but instead that for Poisson distributions to be valid, then all bacteria found in a phage-targeted population must be equally likely to become phage adsorbed. When Poisson distributions fail to describe experimental results, in other words, that can be telling us something. See |
CFU, colony-forming units; PFUs, plaque-forming units.
FIG. 4.Impact of MOIactual on bacterial survival. Assumed is that neither bacteria nor phages are replicating and that bacterial survival is entirely a function of remaining not phage adsorbed. Note that the number of bacteria surviving will be greater to the extent that MOIinput is employed rather than MOIactual and phage adsorption is less than 100%. The y access is calculated simply as e− where n is MOIactual. These calculations otherwise are independent of phage or bacterial densities, as well as the phage adsorption rate constant and time, except to the extent that those values contribute to the magnitude of the indicated MOIactual.
FIG. 5.Defining a minimum inundative phage density (IPDmin). Shown is the simpler of the two formulae (Box 3), which assumes that titers of free phages remain constant over time despite adsorbing bacteria (alternatively, see the second equation, also in Box 3). This is a minimum number because it assumes ideal circumstances, such as that all bacteria are equally accessible to all phages. Variables refer to environmental volume (V), starting concentrations of bacteria (N0, and which in combination with volume gives the starting number of bacteria), ending number of unadsorbed bacteria (NF), the phage adsorption rate constant (k), and the total time over which phage adsorption occurs (t).
Calculating an Inundative Phage Density or Inundative Phage Number
| If we assume a constant phage density, then a minimum inundative phage density (IPDmin) can be defined as, |
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| where |
| If there were 106 bacteria per milliliter in a 10 mL volume, then that would be 107 bacteria in total. If the goal is to reduce that number down to, for example, a total of 10 bacteria over 100 min, then this would require an MOIactual of 13.8, as is equal to ln(107/10) = ln( |
| The Equation (1) calculation can become less realistic at higher bacterial densities, as rates of phage adsorption increase to a point that phage numbers are substantially reduced over short time frames (again, as considered in |
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| which for the same numbers as above is equal instead to 6.2 × 107 = IPDmin, or not much different in this example from the calculated 5.5 × 107 phages/mL delivered by Equation (1). Again, see Abedon[ |
| If we change |
| Unfortunately, it is difficult to modify these calculations to consider spatially structured environments such as biofilms. In part, this is because volumes overlying biofilms can range from very tiny to effectively infinite,[ |
| The latter, a minimum inundative phage |
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| are assumed to adsorb. With Equation (2), by contrast, only 22% of phages will have adsorbed over 100 min, and 1.38/0.22 with rounding error is about 6.2. This is 1.38 × 108 phages/mL for IPNmin distributed over 10 mL versus 6.2 × 108 phages/mL for IPDmin also distributed over 10 mL via the Equation (2) calculation. Of course, if a lower fraction of phages adsorb in either example, then higher phage titers will be required to achieve the same amount of killing of bacteria as based on adsorption by the originally dosed phages. |
| In summary, there exists overall a phage density (a titer, i.e., an IPD) or instead an absolute number of phages (an IPN) that are minimally required to reduce some starting number of bacteria ( |
IPD, inundative phage density; IPN, inundative phage number.
Why Care About the Rest of the Poisson Distribution?
| Emphasis here has been on calculating the fraction of bacteria expected to be unadsorbed by bacteria, that is, with |
| Note that the fraction of bacteria that are phage adsorbed is equal to 1 − POISSON.DIST(0, |