| Literature DB >> 35915849 |
Andrea Marquardt Donovan1, Ana Stephens1, Burcu Alapala1, Allison Monday1, Emily Szkudlarek1, Martha W Alibali1, Percival G Matthews1.
Abstract
Understanding of the equal sign is associated with early algebraic competence in the elementary grades and equation-solving success in middle school. Thus, it is important to find ways to build foundational understanding of the equal sign as a relational symbol. Past work promoted a conception of the equal sign as meaning "the same as". However, recent work highlights another dimension of relational understanding-a substitutive conception, which emphasizes the idea that an expression can be substituted for another equivalent one. This work suggests a substitutive conception may support algebra performance above and beyond a sameness conception alone. In this paper, we share a subset of results from an online intervention designed to foster a relational understanding of the equal sign among fourth and fifth graders (n = 146). We compare lessons focused on a sameness conception alone and a dual sameness and substitutive conception to each other, and we compare both to a control condition. The lessons influenced students' likelihood of producing and endorsing sameness and substitutive definitions of the equal sign. However, the impact of the lessons on students' approaches to missing value equations was less clear. We discuss possible interpretations, and we argue that further research is needed to explore the roles of sameness and substitutive views of the equal sign in supporting structural approaches to algebraic equation solving. © FIZ Karlsruhe 2022.Entities:
Keywords: Algebra; Algebraic thinking; Equal sign; Mathematical equivalence; Sameness; Substitution
Year: 2022 PMID: 35915849 PMCID: PMC9330929 DOI: 10.1007/s11858-022-01405-y
Source DB: PubMed Journal: ZDM ISSN: 1863-9690
Fig. 1Card activity used in the intervention conditions
Sameness and Sameness + Substitutive lesson treatments of 24 + __ = 28 + 58
| Sameness condition | Sameness + Substitutive condition |
|---|---|
When I look at this equation, I notice that 24, on the left side of the equation, and 28, on the right side of the equation, are almost the same amount. What is the difference between 28 and 24? [Wait for student response] | When I look at this equation, I notice that 24 and 28 are almost the same amount. In fact, I know that 24 + 4 = 28. Can you think how we can use this equation to figure out what number goes in the blank in the top equation? [Wait for student response] |
That’s right, 28 – 4 is 24. Can you think about how we can use this fact to figure out what number goes in the blank to make this a true equation? [Wait for student response] | We know that the equal sign means that both sides of the equation are the same amount. Because we know that 28 equals 24 + 4, we can substitute 24 + 4 for this 28 in the original equation. When I do that, I can see that the equation now says 24 + __ = 24 + 4 + 58. Do you notice anything about our equation after we did the substitution? [Wait for student response] |
| Because 24 is 4 less than 28, we know that the number in the blank will be 4 more than 58. This will keep both sides of this equation the same. | Notice that after our substitution, the number 24 is on both sides of the equal sign! How can we use this fact to figure out what number goes in the blank? That’s right! [OR Let me show you]. Since 24 is on both sides of the equal sign, and we know that both sides of the equal sign must be the same amount, we know that the number that goes in the blank will be equal to 4 + 58! |
What is 58 + 4? [Wait for student response] That’s right! 58 + 4 is equal to 62, so 62 is the number that goes in the blank to make this a true equation. | What is 4 + 58? [Wait for student response] That’s right! 4 + 58 is equal to 62, so 62 is the number that goes in the blank to make this a true equation |
Fig. 2Materials for lessons focused on sameness and dual sameness and substitutive conceptions of the equal sign
Fig. 3Equal sign definition and equal sign definition endorsement items. In the results shared here, we focus on the italicized items
Fig. 4Missing value equations
Fig. 5Percent of students offering sameness and substitutive definitions of the equal sign by condition and test
Fig. 6Percent of students endorsing “the equal sign means two amounts are the same” and “the equal sign means the two sides can be swapped” by condition and test
Percent of students correctly solving the missing value items by condition and test
| Control | Sameness | Sameness + Substitutive | ||||
|---|---|---|---|---|---|---|
| Pre | Post | Pre | Post | Pre | Post | |
67 + 84 = __ + 83 ( | 81% | 85% | 93% | 90% | 80% | 89% |
__ + 55 = 37 + 54 ( | 87% | 68% | 75% | 61% | 76% | 84% |
60 + __ = 48 + 24 ( | 68% | 79% | 90% | 65% | 91% | 70% |
18 + 31 + 53 = __ + 63 ( | 65% | 65% | 56% | 48% | 86% | 68% |
Examples of correct structural strategies on missing value equations items
| Equation | Example of correct structural strategy |
|---|---|
| 67 + 84 = __ + 83 | I saw that 83 was one less than 84 so to even it out I knew I had to add 1 onto 67 which was 68 |
| __ + 55 = 37 + 54 | 54 = 55 – 1 __ + 55 = 37 + 55 – 1 55 is on both sides so subtract 37 – 1 which equals 36 |
| 60 + __ = 48 + 24 | 60 + 12 = 48 + 24 because if you took 12 from the 24 and added it to the 48, the 48 would turn into a 60, the equation would look like this 60 + 12 = 60 + 12, on both sides of the = sign are the same thing, 60 + 12 |
| 18 + 31 + 53 = __ + 63 | 53 is 10 less than 63 so take 10 from 18 to make it 8 then add 31 + 8 = 39 |
Fig. 7Percent of students using correct and incorrect structural strategies for each item by condition and test
Fig. 8Percent of missing value items on which students used structural strategies as a function of pretest relational definition and test
Fig. 9Shifts in use of structural strategies on salient and non-salient items by condition. Pretest is indicated on the left and posttest on the right. The lengths of the black, gray, and white bars correspond to the percent of students in each category at the relevant time point
Examples from students in the Sameness condition showing the neither-to-salient and salient-to-both structural strategy paths
| Equation | Pretest | Posttest |
|---|---|---|
| 67 + 84 = __ + 83 | 67 + 84 = 151 – 83 = 68 | 83 is one away from 84 so I added 67 + 1 and I got 68 |
| 60 + __ = 48 + 24 | 48 + 24 = 72 – 60 = 12 | 48 + 24 is 72 72 – 60 is 12 |
| 67 + 84 = __ + 83 | It’s just 67 + 84, except the 84 is decreased by one and the 67 is increased by one | 84 is one more than 83, so the number in the blank has to be one higher than 67, and that’s 68 |
| 60 + __ = 48 + 24 | Since 48 + 24 equal 72, 12 + 60 = 70 too | 60 is 12 numbers higher than 48, so the answer has to be 12 numbers lower than 24 |
Examples from students in the Sameness + Substitutive condition showing the neither-to-salient and salient-to-both structural strategy paths
| Equation | Pretest | Posttest |
|---|---|---|
| 67 + 84 = __ + 83 | 67 + 84 = 151 so subtract 83 from that and that leads to the answer. The answer is 68 | 83 + 1 = 84 so 67 + 1 is 68 because I substituted 1 |
| 60 + __ = 48 + 24 | 48 + 24 = 72 so subtract 60 from 72 and you get the answer which is 12 | 48 + 12 is 60 so 24 – 12 is 12 so adding 60 + 12 is the answer |
| 67 + 84 = __ + 83 | since 83 is 1 less then 84, I just added 1 to 67 | 83 + 1 = 84 so adding 1 to 67 makes both sides the same |
| 60 + __ = 48 + 24 | I could not find a shortcut, so I just did the addition | 60 = 48 + 12 so I subtracted 12 from 24 |