| Literature DB >> 35873439 |
Giovanni Bertoldi1, Gianni Carraro1, Verdiana Ravarotto1, Valentina Di Vico1, Paola Baldini Anastasio1, Nicola Vitturi2, Francesco Francini3, Lucia Federica Stefanelli1, Lorenzo A Calò1.
Abstract
Enzymatic replacement therapy (ERT) is not very effective in halting the progression of Fabry disease (FD) toward cardiovascular (CV)-renal remodeling, particularly in case of late diagnosis. FD patients have increased oxidative stress (OS), critical for the induction of CV-renal remodeling. We investigated the effects of an adjuvant antioxidant treatment to ERT on OS and the possible advantages for related complications. OS was evaluated in 10 patients with FD before ERT, after 12 months of ERT, and after 6 months of adjuvant green tea (GT) to ERT by the following experiments: expression of p22phox; phosphorylation state of MYPT-1 and ERK 1/2 (by western blotting); and quantification of malondialdehyde (MDA) and heme oxygenase (HO)-1 levels (by ELISA). p22 phox and MYPT-1 phosphorylation decreased after ERT and significantly further decreased after GT. ERK 1/2 phosphorylation and MDA levels remained unchanged after ERT, but significantly decreased after GT. HO-1 significantly increased after ERT and further increased after GT. This study provides preliminary data highlighting the antioxidant effect exerted by ERT itself, further amplified by the adjuvant antioxidant treatment with GT. The results of this study provide evidence of the positive effect of early additive antioxidant treatment to reduce OS and prevent/alleviate cardio and cerebrovascular-renal complications related to OS.Entities:
Keywords: enzyme replacement therapy (ERT); epigallocatechin-3-gallate (EGCG); fabry disease; green tea; oxidative stress
Year: 2022 PMID: 35873439 PMCID: PMC9304972 DOI: 10.3389/fnut.2022.924710
Source DB: PubMed Journal: Front Nutr ISSN: 2296-861X
FIGURE 1Flow chart of the study.
Genetic characterization and plasma levels of Lyso Gb3 assessed at baseline (T0) in our cohort of Fabry patients.
| Patient nr. | Gender | G | AA substitution | Lyso Gb3 ng/mL |
| #1 | Female | c.A644G | p.Asn215Ser | 2, 9 |
| #2 | Male | c.A644G | p.Asn215Ser | 5, 3 |
| #3 | Female | c.A644G | p.Asn215Ser | 4, 8 |
| #4 | Male | c.A644G | p.Asn215Ser | 4, 1 |
| #5 | Female | c.A644G | p.Asn215Ser | 1, 2 |
| #6 | Male | c.A644G | p.Asn215Ser | 3, 1 |
| #7 | Female | c.A644G | p.Asn215Ser | 1, 9 |
| #8 | Female | c.1077delT | p.Ile359fs | 4, 7 |
| #9 | Male | c.835C > G | p.Gln279Glu | 2, 7 |
| #10 | Male | c.835C > G | p.Gln279Glu | 3, 3 |
Plasma Lyso Gb3 normal levels are: ≤ 1.8 ng/mL.
*Fs, frame shift.
FIGURE 2(A) p22phox protein expression in FD patients before ERT (T0), after 12 months of ERT treatment (T1) and after 6 months of treatment with green tea on top of ERT (T2). The top part of the panel shows representative Western blot products of p22phox protein expression of one patient. T0 vs. T1, *p = 0.01; T0 vs. T2, **p = 0.001; T1 vs. T2, ***p < 0.001. Repeated measures for one-way ANOVA, p = 0.003. (B) MYPT-1 phosphorylation state in FD patients at baseline (T0), at T1 and at T2. The top part of the panel shows representative Western blot products of p22phox protein expression of one patient. T0 vs. T1 **p < 0.001; T0 vs. T2 ***p < 0.0001; T1 vs. T2, *p = 0.003. Repeated measures for one-way ANOVA, p < 0.001. (C) Phosphorylation state of ERK 1/2 in FD patients at T0, at T1 and at T2. The top part of the panel shows representative Western blot products of p22phox protein expression of one patient. T0 vs. T1 p = ns; T0 vs. T2 *p = 0.003; T1 vs. T2, **p = 0.002. Repeated measures for one-way ANOVA, p = 0.002.
FIGURE 3(A) Lipid peroxidation state. Fluorometric analysis of MDA concentration in FD patients before ERT (T0), after 12 months of ERT treatment (T1) and after 6 months of green tea on top of ERT (T2). T0 vs. T1 p = ns; T1 vs. T2, *p = 0.03; T0 vs. T2, **p = 0.005. ANOVA, p = 0.004. (B) HO-1 protein expression in FD patients at T0, at T1 and at T2. T0 vs. T1, *p = 0.04; T0 vs. T2, **p = 0.001; T1 vs. T2, ***p < 0.001. ANOVA, p = 0.001.