| Task | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.03\\ p > .05\\ \eta _{p}^{2} = 0.00\end{array}$$\end{document}F(1,15)=0.03p>.05ηp2=0.00 | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.50\pm 0.07)\\ \hbox {ME RIGHT}: (0.99\pm 0.01)\end{array}$$\end{document}ME LEFT:(0.50±0.07)ME RIGHT:(0.99±0.01) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.41\\ p > .05\\ \eta _{p}^{2} = 0.03\end{array}$$\end{document}F(1,15)=0.41p>.05ηp2=0.03 | (mean ± SEM) | (mean±SEM) \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.47\pm 0.07)\\ \hbox {ME RIGHT}: (0.97\pm 0.03)\end{array}$$\end{document}ME LEFT:(0.47±0.07)ME RIGHT:(0.97±0.03) |
| Hemisphere | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.10\\ p > .05\\ \eta _{p}^{2} = 0.00\end{array}$$\end{document}F(1,15)=0.10p>.05ηp2=0.00 | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = -6.62\\ \varvec{p < .001}\\d = -1.67\end{array}$$\end{document}t(15)=-6.62p<.001d=-1.67 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.33\\ p > .05\\ \eta _{p}^{2} = 0.02\end{array}$$\end{document}F(1,15)=0.33p>.05ηp2=0.02 | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = -5.81\\ \varvec{p < .001}\\d = -1.45\end{array}$$\end{document}t(15)=-5.81p<.001d=-1.45 |
| \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\mathrm{Task:}\\ \mathrm{Hemisphere}\end{array}$$\end{document}Task:Hemisphere | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 102.81\\ \varvec{p < .001}\\ \eta _{p}^{2} = 0.87\end{array}$$\end{document}F(1,15)=102.81p<.001ηp2=0.87 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 RIGHT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 RIGHTME LEFT∼ME RIGHT | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 71.37\\ \varvec{p < .001}\\ \eta _{p}^{2} = 0.83\end{array}$$\end{document}F(1,15)=71.37p<.001ηp2=0.83 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 RIGHT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 RIGHTME LEFT∼ME RIGHT |
| | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.98\pm 0.02)\\ \hbox {ME RIGHT}: (0.48\pm 0.05)\end{array}$$\end{document}ME LEFT:(0.98±0.02)ME RIGHT:(0.48±0.05) | | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.89\pm 0.06)\\ \hbox {ME RIGHT}: (0.47\pm 0.07)\end{array}$$\end{document}ME LEFT:(0.89±0.06)ME RIGHT:(0.47±0.07) |
| | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}{t(15)} = 9.48\\ \varvec{p < .001}\\ d = 2.37\end{array}$$\end{document}t(15)=9.48p<.001d=2.37 | | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = 4.59\\ \varvec{p < .001}\\ d = 1.15\end{array}$$\end{document}t(15)=4.59p<.001d=1.15 |
| fNIRS \documentclass[12pt]{minimal}
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\begin{document}$$\Delta [HbO]$$\end{document}Δ[HbO] | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 LEFT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 LEFTME LEFT∼ME RIGHT | fNIRS \documentclass[12pt]{minimal}
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\begin{document}$$\Delta [HbR]$$\end{document}Δ[HbR] | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 LEFT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 LEFTME LEFT∼ME RIGHT |
| Task | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.00\\ p > .05\\ \eta _{p}^{2} = 0.00\end{array}$$\end{document}F(1,15)=0.00p>.05ηp2=0.00 | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.42 \pm 0.10)\\ \hbox {ME RIGHT}: (0.92 \pm 0.04)\end{array}$$\end{document}ME LEFT:(0.42±0.10)ME RIGHT:(0.92±0.04) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 1.03\\ p > .05\\ \eta _{p}^{2} = 0.06\end{array}$$\end{document}F(1,15)=1.03p>.05ηp2=0.06 | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.61 \pm 0 .08)\\ \hbox {ME RIGHT:} (0.89 \pm 0.05)\end{array}$$\end{document}ME LEFT:(0.61±0.08)ME RIGHT:(0.89±0.05) |
| Hemisphere | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.06\\ p > .05\\ \eta _{p}^{2} = 0.00\end{array}$$\end{document}F(1,15)=0.06p>.05ηp2=0.00 | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = - 4.96 \\ \varvec{p < .001}\\{\text{d = }} - {\text{1.24}} \\ \end{array}$$\end{document}t(15)=-4.96p<.001d =-1.24 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 1.37\\ p > .05\\ \eta _{p}^{2} = 0.08\end{array}$$\end{document}F(1,15)=1.37p>.05ηp2=0.08 | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = -2.45\\ \varvec{p < .05}\\ d = -0.61\end{array}$$\end{document}t(15)=-2.45p<.05d=-0.61 |
| \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\mathrm{Task:}\\ \mathrm{Hemisphere}\end{array}$$\end{document}Task:Hemisphere | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 45.47\\ \varvec{p < .001}\\ \eta _{p}^{2} = 0.75\end{array}$$\end{document}F(1,15)=45.47p<.001ηp2=0.75 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 RIGHT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 RIGHTME LEFT∼ME RIGHT | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 33.62\\ \varvec{p < .001}\\ \eta _{p}^{2} = 0.69\end{array}$$\end{document}F(1,15)=33.62p<.001ηp2=0.69 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 RIGHT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 RIGHTME LEFT∼ME RIGHT |
| | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.91\pm 0.06)\\ \hbox {ME RIGHT}: (0.40\pm 0.09)\end{array}$$\end{document}ME LEFT:(0.91±0.06)ME RIGHT:(0.40±0.09) | | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.92\pm 0.05)\\ \hbox {ME RIGHT}: (0.47\pm 0.07)\end{array}$$\end{document}ME LEFT:(0.92±0.05)ME RIGHT:(0.47±0.07) |
| | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = 3.79\\ \varvec{p < .01}\\d = 0.95\end{array}$$\end{document}t(15)=3.79p<.01d=0.95 | | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = 5.09\\ \varvec{p <.001}\\d = 1.27\end{array}$$\end{document}t(15)=5.09p<.001d=1.27 |
| fNIRS \documentclass[12pt]{minimal}
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\begin{document}$$\Delta [HbO]$$\end{document}Δ[HbO] LABELED | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 LEFT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 LEFTME LEFT∼ME RIGHT | fNIRS \documentclass[12pt]{minimal}
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\begin{document}$$\Delta [HbR]$$\end{document}Δ[HbR] LABELED | \documentclass[12pt]{minimal}
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| Task | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.01\\ p > .05\\ \eta _{p}^{2} = 0.00\end{array}$$\end{document}F(1,15)=0.01p>.05ηp2=0.00 | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.39 \pm 0.09)\\ \hbox {ME RIGHT}: (0.85 \pm 0.07)\end{array}$$\end{document}ME LEFT:(0.39±0.09)ME RIGHT:(0.85±0.07) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 2.20\\ p > .05\\ \eta _{p}^{2} = 0.13\end{array}$$\end{document}F(1,15)=2.20p>.05ηp2=0.13 | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.65 \pm 0.09)\\ \hbox {ME RIGHT}: (0.79 \pm 0.08)\end{array}$$\end{document}ME LEFT:(0.65±0.09)ME RIGHT:(0.79±0.08) |
| Hemisphere | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 0.07\\ p > .05\\ \eta _{p}^{2} = 0.00\end{array}$$\end{document}F(1,15)=0.07p>.05ηp2=0.00 | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = -3.97\\ \varvec{p < .01}\\d = -0.99\end{array}$$\end{document}t(15)=-3.97p<.01d=-0.99 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 1.38\\ p > .05\\ \eta _{p}^{2} = 0.08\end{array}$$\end{document}F(1,15)=1.38p>.05ηp2=0.08 | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = -1.03\\p > .05\\d = -0.26\end{array}$$\end{document}t(15)=-1.03p>.05d=-0.26 |
| \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\mathrm{Task:}\\ \mathrm{Hemisphere}\end{array}$$\end{document}Task:Hemisphere | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 50.61\\ \varvec{p < .001}\\ \eta _{p}^{2} = 0.77\end{array}$$\end{document}F(1,15)=50.61p<.001ηp2=0.77 | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {M1 RIGHT}\\ \hbox {ME LEFT} \sim \hbox {ME RIGHT}\end{array}$$\end{document}M1 RIGHTME LEFT∼ME RIGHT | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}F(1, 15) = 14.94\\ \varvec{p < .01}\\ \eta _{p}^{2} = 0.50\end{array}$$\end{document}F(1,15)=14.94p<.01ηp2=0.50 | \documentclass[12pt]{minimal}
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| | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.87 \pm 0.07)\\ \hbox {ME RIGHT}: (0.40 \pm 0.08)\end{array}$$\end{document}ME LEFT:(0.87±0.07)ME RIGHT:(0.40±0.08) | | (mean ± SEM) | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}\hbox {ME LEFT}: (0.87 \pm 0.06)\\ \hbox {ME RIGHT}: (0.43 \pm 0.09)\end{array}$$\end{document}ME LEFT:(0.87±0.06)ME RIGHT:(0.43±0.09) |
| | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = 3.86\\ \varvec{p <.01}\\d = 0.97\end{array}$$\end{document}t(15)=3.86p<.01d=0.97 | | t-test | \documentclass[12pt]{minimal}
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\begin{document}$$\begin{array}{l}t(15) = 3.81\\ \varvec{p < .01}\\d = 0.95\end{array}$$\end{document}t(15)=3.81p<.01d=0.95 |