| Literature DB >> 35153408 |
Mohamed M M El-Sokary1, Al-Shimaa Al-H H El-Naby1, Amal R Abd El Hameed2, Karima Gh M Mahmoud2, T H Scholkamy3.
Abstract
BACKGROUND AND AIM: Despite many trials, buffalo embryos have poor cryosurvivability because of their high lipid content. L-carnitine was found to be a lipid-reducing agent when added to oocyte and embryo culture media. The study aimed to determine the most effective concentration of L-carnitine to improve the oocyte developmental competence and cryotolerance of buffalo embryos.Entities:
Keywords: L-carnitine; antioxidant; buffalo embryos; cryotolerance
Year: 2021 PMID: 35153408 PMCID: PMC8829399 DOI: 10.14202/vetworld.2021.3164-3169
Source DB: PubMed Journal: Vet World ISSN: 0972-8988
Developmental competence of buffalo oocytes after culture supplementation with different concentrations of L-carnitine (Mean±SE).
| L-carnitine concentration | Total no. of inseminated oocytes | Cleavage | Morula | Blastocyst |
|---|---|---|---|---|
|
|
|
| ||
| No. (%) | No. (%) | No. (%) | ||
| 0 mM | 91 | 50 (54.8±1.6)[ | 34 (36.9±2.6)[ | 13 (14.6±1.1)[ |
| 0.25 mM | 81 | 48 (59.6±2.0)ab | 31 (39.1±5.1)ab | 16 (19.7±0.9)ab |
| 0.5 mM | 76 | 52 (66.7±4.2)[ | 37 (48.3±0.8)[ | 17 (21.7±1.8)ab |
| 1 mM | 56 | 36 (63.5±3.2)ab | 25 (43.9±3.3)ab | 13 (24.3±3.8)[ |
Percent of total inseminated oocytes. No. = number.
,
Values inside similar column without common superscripts differ p<0.05, three replicates (ANOVA test). ANOVA=Analysis of variance, SE=Standard error
Cryotolerance of buffalo embryos after culture supplementation with different concentrations of L-carnitine (Mean±SE).
| L-carnitine concentration | Total no. of inseminated oocytes | Cleavage | Morula | Blastocyst |
|---|---|---|---|---|
|
|
|
| ||
| No. (%) | No. (%) | No. (%) | ||
| 0 mM | 91 | 50 (54.8±1.6)[ | 34 (36.9±2.6)[ | 13 (14.6±1.1)[ |
| 0.25 mM | 81 | 48 (59.6±2.0)ab | 31 (39.1±5.1)ab | 16 (19.7±0.9)ab |
| 0.5 mM | 76 | 52 (66.7±4.2)[ | 37 (48.3±0.8)[ | 17 (21.7±1.8)ab |
| 1 mM | 56 | 36 (63.5±3.2)ab | 25 (43.9±3.3)ab | 13 (24.3±3.8)[ |
,
Values inside similar column without common superscripts differ p<0.05, three replicates (ANOVA test). ANOVA=Analysis of variance, SE=Standard error