| Literature DB >> 35073944 |
Noemi Graziano1, Carlo Agostoni2,3,4, Francesca Chiaraviglio5, Céline Betti5, Arianna Piffer6, Mario G Bianchetti6, Gregorio P Milani1,7.
Abstract
BACKGROUND: The biochemical hallmarks of transient pseudo-hypoaldosteronism associated with a pyelonephritis include hyponatremia, hyperkalemia, and acidosis. We tested if the kidney-urinary tract ultrasound helps in predicting the diagnosis of overt pseudo-hypoaldosteronism in infants with a pyelonephritis. CASESEntities:
Keywords: Acidosis; Aldosterone; children; infants; Hyponatremia; Infection; Pyelonephritis; Sonography
Mesh:
Year: 2022 PMID: 35073944 PMCID: PMC8785504 DOI: 10.1186/s13052-022-01203-y
Source DB: PubMed Journal: Ital J Pediatr ISSN: 1720-8424 Impact factor: 2.638
Clinical and laboratory characteristics of infants without and with laboratory features consistent with the diagnosis of transient pseudo-hypoaldosteronism. Data are presented as frequency or as median and interquartile range
| Pseudo-hypoaldosteronism | |||
|---|---|---|---|
| Without | With | ||
| 54 | 17 | ||
| Demographics | |||
| Males: Females | 31: 23 | 11: 6 | 0.76 |
| Age, months | 4.8 [2.2–11] | 4.0 [3.3–7.3] | 0.93 |
| Blood values | |||
| Hemoglobin, g/L | 113 [106–122] | 114 [104–122] | 0.56 |
| Leukocyte count, 109/L | 14.4 [11.6–19.9] | 14.6 [11.5–19.8] | 0.76 |
| Platelet count, 109/L | 415 [319–470] | 416 [322–469] | 0.48 |
| C-reactive protein, mg/L | 30 [11–90] | 35 [15–60] | 0.42 |
| Sodium, mmol/L | 134 [133–136] | 131 [129–133] | • |
| Potassium mmol/L | 4.7 [4.3–4.9] | 5.5 [4.7–6.0] | • |
| Bicarbonate, mmol/L | 24 [22–26] | 19 [18–21] | • |
| Creatinine, μmol/L | 27 [20–33] | 28 [25–31] | 0.53 |
| Urea, mmol/L | 2.8 [2.2–3.5] | 2.4 [2.2–3.7] | 0.33 |
| Altered kidney-urinary tract ultrasound | 7* | 4✙ | 0.44 |
•the two study groups were not compared with respect to these parameters, because a statistically significant difference is predictable; * UTD classification stage 2: N = 1; stage 3: N = 6; ✙UTD classification stage 2: N = 1; stage 3: N = 3