| Literature DB >> 34137610 |
Małgorzata Kwiatkowska1, Jarosław Błaszczyk1, Lesław Sieroń2, Piotr Kiełbasiński1.
Abstract
A series of enantiomerically pure derivatives of 6-(1-hydroxyalkyl)-1,3,5-triaza-7-phosphatricyclo[3.3.1.1]decane 5 were successfully synthesized for the first time. A series of hydrolytic enzymes was applied in a stereoselective acetylation performed under kinetic resolution conditions. Although the secondary alcohols: α-aryl-hydroxymethyl-PTA (phosphines) 5b-d', PTA-oxides 8b-d', and PTA-sulfides 9b-d' were found to be totally unreactive in the presence of all the enzymes and various conditions applied, the primary alcohols, i.e., the hydroxymethyl derivatives PTA oxide 8a and PTA sulfide 9a, were successfully resolved into enantiomers with moderate to good enantioselectivity (up to 95%). The absolute configurations of the products were determined by an X-ray analysis and chemical correlation.Entities:
Mesh:
Substances:
Year: 2021 PMID: 34137610 PMCID: PMC8279493 DOI: 10.1021/acs.joc.0c02586
Source DB: PubMed Journal: J Org Chem ISSN: 0022-3263 Impact factor: 4.354
Figure 1Functionalization of PTA.
Scheme 1Reaction of PTA-Li 2 with Electrophiles
Scheme 2Enzymatic Synthesis of Enantiomerically Pure Phosphine Oxides
Scheme 3Asymmetric Bioreduction of β-Activated Vinylphosphonates
Scheme 4Synthesis of Substrates for Enzymatic Transformations
Racemic Substrates for Enzymatic Transformationsa
| phosphine | phosphine
oxide | phosphine
sulfide | ||||||
|---|---|---|---|---|---|---|---|---|
| symbol | R | yield (%) | 31P NMR (δ) | yield (%) | 31P NMR (δ) | yield (%) | 31P NMR (δ) | remarks |
| H | 45 | –102.2 | 24 | –1.9 | 30 | –15.5 | ||
| Ph | 15 | –106.5 | 40 | –5.1 | 41 | –17.3 | diastereomers | |
| Ph | 21 | –103.0 | 41 | –3.7 | 42 | –13.5 | ||
| 16 | –106.7 | 31 | –5.0 | 32 | –17.4 | diastereomers | ||
| 6 | –102.4 | 13 | –4.0 | 14 | –13.3 | |||
| 17 | –106.2 | 30 | –5.0 | 32 | –17.0 | diastereomers | ||
| 7 | –102.7 | 10 | –3.8 | 11 | –13.0 | |||
Conditions: 3.2 mmol of PTA, 3.3 mmol of n-BuLi, 3.5 mmol of aldehyde, THF (20 mL) under argon then an excess of 35% aqueous solution of H2O2 or elemental sulfur (2 equiv)
Scheme 5Enzymatic Kinetic Resolution of Racemic Substrates 5–9
Enzymatic Kinetic Resolution of Racemic Substrates
| recovered
substrate | product,
after hydrolysis | |||||||||
|---|---|---|---|---|---|---|---|---|---|---|
| substrate | enzyme | solvent | time (day) | yield (%) | ee | abs conf | yield (%) | ee | abs conf | |
| CAL-B | CH2Cl2 | 2 | 14 | 95 | 44 | 64 | 16 | |||
| CRL | CH2Cl2 | 2 | 32 | 54 | 59 | 12 | 2 | |||
| TL | CH2Cl2 | 8 | 32 | 72 | 58 | 38 | 4.5 | |||
| Mix: CAL-B, PFL, PS, CRL, CCL | CH2Cl2 | 7 | 48 | 68 | 47 | 72 | 13 | |||
| Mix: PPL, MJ, AK, LPL, AH | CH2Cl2 | 10 | 74 | 6 | 25 | 30 | 2 | |||
| PCP | CH2Cl2 | 7 | ||||||||
| WGL | CH2Cl2 | 7 | ||||||||
| PA | CH2Cl2 | 7 | ||||||||
| MJ | CH2Cl2 | 7 | ||||||||
| LPL | CH2Cl2 | 7 | ||||||||
| PFL | CH2Cl2 | 7 | ||||||||
| CCL | CH2Cl2 | 7 | ||||||||
| TL | CH2Cl2 | 8 | 34 | 44 | 36 | 32 | 3 | |||
| Mix: PFL, CAL-B, PS, CRL, CCL | CH2Cl2 | 7 | 41 | 33 | 54 | 30 | 2.5 | |||
| CAL-B | CH2Cl2 | 2 | 59 | 23 | 32 | 27 | 2 | |||
| CRL | CH2Cl2 | 2 | 53 | 24 | 27 | 32 | 2.5 | |||
| PFL | CH2Cl2 | 22 | 70 | 7 | 20 | 14 | 1.5 | |||
| CCL | CH2Cl2 | 22 | 46 | 12 | 19 | 19 | 2 | |||
| CRL | C6H12 | 4 | 38 | 10 | 13 | 7 | 1 | |||
| CRL | MeCN | 4 | 49 | 10 | 1 | 9 | 1.5 | |||
| CRL | Et2O | 4 | 47 | 10 | 15 | 11 | 1.5 | |||
| CRL | toluene | 4 | 45 | 18 | 15 | 20 | 2 | |||
Enzymes: CAL-B, Candida antarctica lipase; PFL, Pseudomonas fluorescens lipase; PS, Pseudomonas species lipase; CRL, Candida rugose lipase; CCL, Candida cylindracea lipase; TL, lipase from Pseudomonas stutzeri; PPL, Porcine pancreas lipase; MJ, Mucor javanicus lipase; AK, lipase AK (AMANO); LPL, lipoprotein lipase; PCP, papain from Carica papaya; WGL, wheat germ lipase; AH, lipase AH (AMANO); PA, penicillin amidase.
The ee was determined using HPLC with chiral columns: AS-H, n-hexane (i-PrOH/EtOH 4:1) 75:25, Fl. 0.5 mL/min for P=S derivatives 9a and OD-H, n-hexane:(MeOH/EtOH 1:1) 75:25, Fl. 0.5 mL/min for P=O derivatives 8a
The enantiomer ratio E = ln[1 – c(1 + eep)]/ln[1 – c(1 – eep)], c = ees/(ees + eep).[13]
Figure 2Ellipsoidal view (ORTEP) of the enantiomeric molecule (R)-9a (left) and (S)-9a (right), showing the single molecules present in the asymmetric units, the atom numbering scheme, and the absolute configuration of the substituents at the carbon atom C2. Ellipsoids are drawn with 50% probability level.
Figure 3Fragment of the packing of molecules in the crystal of compound 9a with a marked chain of intermolecular hydrogen bonds extending along the axis b of the unit cell.
Hydrogen-Bonding Geometry for 9a (Å/deg)
| H···A | D···A | D–H···A | symmetry | |
|---|---|---|---|---|
| O1–H1···N1 | 2.41/2.41 | 2.867(4)/2.872(3) | 115/115 | |
| O1–H1···N2 | 2.09/2.08 | 2.800(4)/2.798(3) | 143/143 | 1 – |
| C1–H2···N3 | 2.56/2.55 | 3.534(5)/3.531(4) | 166/167 | 1 + |
| C1–H11···O1 | 2.20/2.23 | 3.151(7)/3.153(5) | 162/162 | –1/2 + |
Scheme 6Determination of the Absolute Configuration of 8a by a Chemical Correlation