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\begin{document}$$ {\mathcal B} $$\end{document}ℬ
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\begin{document}$${k}_{e}\langle \delta {q}^{2}\rangle /(Td)$$\end{document}ke〈δq2〉/(Td)
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\begin{document}$$l$$\end{document}l
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\begin{document}$$\sqrt{4-{ {\mathcal B} }^{2}}$$\end{document}4−ℬ2
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\begin{document}$${l}_{1}$$\end{document}l1
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\begin{document}$$\sqrt{1-{ {\mathcal B} }^{2}}$$\end{document}1−ℬ2
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\begin{document}$${C}_{res}^{T}$$\end{document}CresT
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\begin{document}$$80\,{2}^{1/5}\,{d}^{2}{C}_{\epsilon }m/(21\sqrt{\pi }{m}^{8/5})$$\end{document}8021/5d2Cϵm/(21πm8/5)
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\begin{document}$${C}_{agg}^{T}$$\end{document}CaggT
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\begin{document}$${d}^{2}\mathrm{/(8}\sqrt{\pi m})$$\end{document}d2/(8πm)
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\begin{document}$${C}_{res}^{q}$$\end{document}Cresq
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\begin{document}$$1.4080\,{d}^{2}{C}_{{\rm{\Delta }}q}^{2}\mathrm{(2}+\eta \mathrm{)(4/}m{)}^{\eta +\mathrm{1/2}}/\pi $$\end{document}1.4080d2CΔq2(2+η)(4/m)η+1/2/π
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\begin{document}$${C}_{agg}^{q}$$\end{document}Caggq
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\begin{document}$$4{d}^{2}/\sqrt{\pi m}$$\end{document}4d2/πm
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\begin{document}$${C}_{agg}^{n}$$\end{document}Caggn
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\begin{document}$${d}^{2}\mathrm{/(2}\sqrt{\pi m})$$\end{document}d2/(2πm)
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\begin{document}$${a}_{1}^{T}$$\end{document}a1T
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\begin{document}$$ {\mathcal B} \mathrm{(8}-5{ {\mathcal B} }^{2})l+\pi \mathrm{(16}-10{ {\mathcal B} }^{2}+3{ {\mathcal B} }^{4})$$\end{document}ℬ(8−5ℬ2)l+π(16−10ℬ2+3ℬ4)
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\begin{document}$${a}_{2}^{T}$$\end{document}a2T
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\begin{document}$$-\,32+20{ {\mathcal B} }^{2}-6{ {\mathcal B} }^{4}$$\end{document}−32+20ℬ2−6ℬ4
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\begin{document}$${a}_{3}^{T}$$\end{document}a3T
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\begin{document}$$l\mathrm{(2}\pi {({ {\mathcal B} }^{2}-\mathrm{4)}}^{2}+ {\mathcal B} (\,-\,32+28{ {\mathcal B} }^{2}+{ {\mathcal B} }^{4}))$$\end{document}l(2π(ℬ2−4)2+ℬ(−32+28ℬ2+ℬ4))
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\begin{document}$${a}_{4}^{T}$$\end{document}a4T
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\begin{document}$$-\,\mathrm{4(32}-20{ {\mathcal B} }^{2}+9{ {\mathcal B} }^{4})$$\end{document}−4(32−20ℬ2+9ℬ4)
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\begin{document}$${a}_{5}^{T}$$\end{document}a5T
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\begin{document}$$l {\mathcal B} (\,-\,32+28{ {\mathcal B} }^{2}+{ {\mathcal B} }^{4})$$\end{document}lℬ(−32+28ℬ2+ℬ4)
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\begin{document}$$+\,2\pi ({ {\mathcal B} }^{2}\mathrm{(20}-8l)+{ {\mathcal B} }^{4}(\,-\,9+l)+\mathrm{16(}\,-\,2+l))$$\end{document}+2π(ℬ2(20−8l)+ℬ4(−9+l)+16(−2+l))
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\begin{document}$${a}_{6}^{T}$$\end{document}a6T
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\begin{document}$$\mathrm{4(32}-20{ {\mathcal B} }^{2}+9{ {\mathcal B} }^{4})$$\end{document}4(32−20ℬ2+9ℬ4)
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\begin{document}$${a}_{1}^{q}$$\end{document}a1q
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\begin{document}$$2 {\mathcal B} l({ {\mathcal B} }^{2}-\mathrm{1)}-\pi \mathrm{(4}-2{ {\mathcal B} }^{2}+{ {\mathcal B} }^{4})$$\end{document}2ℬl(ℬ2−1)−π(4−2ℬ2+ℬ4)
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\begin{document}$${a}_{2}^{q}$$\end{document}a2q
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\begin{document}$$\mathrm{2(4}-2{ {\mathcal B} }^{2}+{ {\mathcal B} }^{4})$$\end{document}2(4−2ℬ2+ℬ4)
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\begin{document}$${a}_{3}^{q}$$\end{document}a3q
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\begin{document}$$16l\sqrt{\pi }{l}_{1}{\mathrm{(4}-5{ {\mathcal B} }^{2}+{ {\mathcal B} }^{4})}^{2}$$\end{document}16lπl1(4−5ℬ2+ℬ4)2
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\begin{document}$${a}_{4}^{q}$$\end{document}a4q
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\begin{document}$$-\,\sqrt{\pi } {\mathcal B} l(\pi ({ {\mathcal B} }^{2}-\mathrm{4)(1}+2{ {\mathcal B} }^{2})$$\end{document}−πℬl(π(ℬ2−4)(1+2ℬ2)
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\begin{document}$$+\,2 {\mathcal B} {l}_{1}(\,-\,8-54{ {\mathcal B} }^{2}+33{ {\mathcal B} }^{4}+2{ {\mathcal B} }^{6}))$$\end{document}+2ℬl1(−8−54ℬ2+33ℬ4+2ℬ6))
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\begin{document}$${a}_{5}^{q}$$\end{document}a5q
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\begin{document}$$2\sqrt{\pi } {\mathcal B} {l}^{5}\mathrm{(1}+2{ {\mathcal B} }^{2})$$\end{document}2πℬl5(1+2ℬ2)
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\begin{document}$${a}_{6}^{q}$$\end{document}a6q
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\begin{document}$$16\sqrt{\pi } {\mathcal B} {l}_{1}^{5}\mathrm{(4}+5{ {\mathcal B} }^{2})$$\end{document}16πℬl15(4+5ℬ2)
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\begin{document}$${a}_{7}^{q}$$\end{document}a7q
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\begin{document}$$8l\sqrt{\pi }{l}_{1}{\mathrm{(4}-5{ {\mathcal B} }^{2}+{ {\mathcal B} }^{4})}^{2}$$\end{document}8lπl1(4−5ℬ2+ℬ4)2
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\begin{document}$${a}_{8}^{q}$$\end{document}a8q
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\begin{document}$$-\,\sqrt{\pi } {\mathcal B} {l}^{5}\mathrm{(1}+2{ {\mathcal B} }^{2})$$\end{document}−πℬl5(1+2ℬ2)
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\begin{document}$$\sqrt{\pi } {\mathcal B} {l}_{1} {\mathcal B} l\mathrm{(8}+54{ {\mathcal B} }^{2}-33{ {\mathcal B} }^{4}-2{ {\mathcal B} }^{6})$$\end{document}πℬl1ℬl(8+54ℬ2−33ℬ4−2ℬ6)
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\begin{document}$${a}_{10}^{q}$$\end{document}a10q
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\begin{document}$$8\sqrt{\pi } {\mathcal B} {l}_{1}{({ {\mathcal B} }^{2}-\mathrm{1)}}^{2}\mathrm{(4}+5{ {\mathcal B} }^{2})$$\end{document}8πℬl1(ℬ2−1)2(4+5ℬ2)
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\begin{document}$${a}_{1}^{n}$$\end{document}a1n
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\begin{document}$$-\,{ {\mathcal B} }^{2}{l}^{3}$$\end{document}−ℬ2l3
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\begin{document}$${l}_{1}l {\mathcal B} (\,-\,4+7{ {\mathcal B} }^{2})+{l}_{1}\pi ({ {\mathcal B} }^{2}-1)(8-4l+{ {\mathcal B} }^{2}(\,-\,6+l))$$\end{document}l1lℬ(−4+7ℬ2)+l1π(ℬ2−1)(8−4l+ℬ2(−6+l))
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\begin{document}$${a}_{3}^{n}$$\end{document}a3n
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\begin{document}$$4{l}_{1}\mathrm{(4}-7{ {\mathcal B} }^{2}+3{ {\mathcal B} }^{4})$$\end{document}4l1(4−7ℬ2+3ℬ4)
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\begin{document}$${a}_{4}^{n}$$\end{document}a4n
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\begin{document}$$-\,{ {\mathcal B} }^{2}{l}^{3}$$\end{document}−ℬ2l3
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\begin{document}$${a}_{5}^{n}$$\end{document}a5n
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\begin{document}$${l}_{1}l( {\mathcal B} (\,-\,4+7{ {\mathcal B} }^{2})+\pi \mathrm{(4}-5{ {\mathcal B} }^{2}+{ {\mathcal B} }^{4}))$$\end{document}l1l(ℬ(−4+7ℬ2)+π(4−5ℬ2+ℬ4))
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\begin{document}$${a}_{6}^{n}$$\end{document}a6n
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\begin{document}$$-\,4{l}_{1}(4-7{ {\mathcal B} }^{2}+3{ {\mathcal B} }^{4})$$\end{document}−4l1(4−7ℬ2+3ℬ4)
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