Literature DB >> 30137739

Majorization involving the cyclic moving average.

Tao Zhang1, Huan-Nan Shi2, Bo-Yan Xi3, Alatancang Chen1.   

Abstract

We solve an open problem on some majorization inequalities involving the cyclic moving average.

Entities:  

Keywords:  Cyclic moving average; Inequality

Year:  2018        PMID: 30137739      PMCID: PMC6022537          DOI: 10.1186/s13660-018-1737-4

Source DB:  PubMed          Journal:  J Inequal Appl        ISSN: 1025-5834            Impact factor:   2.491


Introduction

We first recall two definitions.

Definition 1.1

([1]) For fixed , let and be two n-tuples of real numbers. x is said to be majorized by y (in symbols, ) if where and are rearrangements of x and y in descending order. Let . A function is said to be a Schur-convex function (shortly, an S-convex function) if For example: In 2006, I. Olkin, one of the authors of the book [1], wrote a letter to K. Z. Guan, referring to the following interesting question: is it true that However, a proof for remains elusive (see [1], p. 63). In 2010, Shi [2] proved that (1) holds when , and , . In this paper, we prove that (1) holds for any and . For any , let be the ordered component of the sequence . We denote

Lemmas and corollaries

For proving our main results, we need the following lemmas.

Lemma 2.1

Let and . Then

Proof

For any and , we have Note that , so we can induce that  □ if , that is, , then . It follows that . if , that is, , then . Since , we have . So . It follows that . . Therefore (2) holds. From the proof of Lemma 2.1 it is easy to deduce the following:

Corollary 2.2

Let , , and let . For any , there exist and such that and

Lemma 2.3

Let , , and . If then If then For , if then If then For , if then For , if then By Lemma 2.1 we have It follows that Thus we have By the left inequality of (3) we have Note that , so we have Therefore By Lemma 2.1 we have By the right inequality of (4) we get Note that , so we have This means that By (5) we get Note that and , so we have It follows that and Therefore (6) holds. By (7) we get Since , we have It follows that By (8) we have Note that and , so we have This means that By (9) we get Note that and , so we have It follows that So we get Therefore Note that , so we have It follows that Therefore

Lemma 2.4

Let , , , and . If , then If , then For , if , then We only prove (i). Using a similar method, we can obtain (ii) and (iii). By Lemma 2.1 we have By Corollary 2.2 we let where , , and . It is clear that Next, we prove that and . If , which means that the right-hand side of (12) includes , then by (11) the right-hand side of (12) should include and , so we have This is a contradiction with (13). If , then by (13) we have . Together with (11), we get So the right-hand side of (12) must include , which means that . This is a contradiction with . Therefore and . So (10) holds. □

Corollary 2.5

Let , , , and , and let For , we have For , we have For and , must be one of the following two cases: or If , by (14) we have By Lemma 2.3(i) we have and then by Lemma 2.4(i) we can induce that (15) holds. If , then by (14) we have By Lemma 2.3(ii) we have and then by Lemma 2.4(i) we can induce that (16) holds. By Corollary 2.2 we let where , , and . Then we have Next, we prove that or . If , then by Lemma (2.3)(iii) we have . So we get Thus the right-hand side of (17) includes , which means that . Therefore This is a contradiction with (18). If , then by (18) we have . By Lemma 2.3(iii) we get . It follows that So the right-hand side of (17) must include . Therefore This is a contradiction with . Thus or . □ In a similar way as in Corollary 2.5, we can prove the following corollaries.

Corollary 2.6

Let , , , and . If , then must be one of the following two cases: or If , then must be one of the following two cases: or

Corollary 2.7

Let , , , and , and let . If then we have: if , then if , then must be one of the following two cases: or

Lemma 2.8

Let , , , and , and let . If then By a simple calculation we obtain By (19) we have It follows that So we have Note that Thus we can induce that This means that (20) holds. □

Lemma 2.9

Let , , , and , and let . If then Note that By (21) we have It follows that So we can induce that Since we have This means that (22) holds. □

Main results

We are now in a position to prove our main results (1) in two cases: and .

Theorem 3.1

For any , we have It is clear that (23) holds if . Next, let . Then we have For , we prove that in the following two cases:  □ If , then If , then So (23) holds.

Theorem 3.2

For any and , we have It is clear that (24) holds for any , and for , . Next, let and . For any and , let , and let Next, we prove that in the following two cases:  □ If and , then by Corollary 2.7(i) and Lemma 2.8 we get If and , then by Corollary 2.7(ii), Lemma 2.8, and Lemma 2.9 we get Note that so (24) holds.

Discussion

In the theory of majorizations, there are two key concepts, majorizing relations and Schur-convex functions. Majorizing relations are weaker ordered relations among vectors, and Shur-convex functions are an extension of classical convex functions. Combining these two objects is an effective method of constructing inequalities. In the theory of majorization, there are two important and fundamental objects, establishing majorizing relations among vectors and finding various Schur-convex functions. Majorizing relations deeply characterize intrinsic connections among vectors, and combining a new majorizing relation with suitable Schur-convex functions can lead to various interesting inequalities; see [3-13].
  1 in total

1.  Schur-convexity, Schur-geometric and Schur-harmonic convexity for a composite function of complete symmetric function.

Authors:  Huan-Nan Shi; Jing Zhang; Qing-Hua Ma
Journal:  Springerplus       Date:  2016-03-08
  1 in total

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