| Literature DB >> 29143648 |
Anand N Vidyashankar1, Pablo D Jimenez Castro2, Ray M Kaplan3.
Abstract
BACKGROUND: Initial studies of heartworm preventive drugs all yielded an observed efficacy of 100% with a single dose, and based on these data the US Food and Drug Administration (FDA) required all products to meet this standard for approval. Those initial studies, however, were based on just a few strains of parasites, and therefore were not representative of the full assortment of circulating biotypes. This issue has come to light in recent years, where it has become common for studies to yield less than 100% efficacy. This has changed the landscape for the testing of new products because heartworm efficacy studies lack the statistical power to conclude that finding zero worms is different from finding a few worms.Entities:
Keywords: Canine heartworm; Dirofilaria immitis; Efficacy; Macrocyclic lactone; Parametric bootstrap; Statistical
Mesh:
Substances:
Year: 2017 PMID: 29143648 PMCID: PMC5688406 DOI: 10.1186/s13071-017-2440-x
Source DB: PubMed Journal: Parasit Vectors ISSN: 1756-3305 Impact factor: 3.876
Efficacy data for various trials reported in Snyder et al. [10] and [11] using the MP3 strain of Dirofilaria immitis and treatment using milbemycin oxime (0.5–0.75 mg/kg) and spinosad (30–45 mg/kg)
| Treatment regimena,b | Number of worms recovered in treated dogs | Geometric mean | Model-based mean | Model-based 95% CI |
|---|---|---|---|---|
| 30 daysa | 1 | 99.8 | 99.8 | 99.2, 100 |
| 30 daysb | 5 | 98.99 | 98.51 | 97.36, 99.44 |
| 45 daysb | 5 | 98.87 | 98.52 | 97.37, 99.45 |
| 30 and 60 daysb | 1 | 99.63 | 99.51 | 98.59, 100 |
| 15 and 45 daysb | 0 | 100 | 100 | N/A |
| 30, 60 and 90 daysb | 0 | 100 | 100 | N/A |
One, two or three doses of drug were administered either 30, 45, 30/60, 15/45, or 30/60/90 days post inoculation with infective L3. Model based mean and 95% confidence intervals (CI) were calculated using the parametric bootstrap model described in the text
aData from Snyder et al., [10]
bData from Snyder et al., [11]
Output of a simulation experiment based on an experiment where treated and non-treated control groups each with 10 dogs are inoculated with 50 L3 per dog, with a mean establishment rate of 50%. Simulation was repeated 1000X, and values represent the percent of times 0, 1, 2, or >2 worms were observed at five different efficacy levels
| % of times you will see 0, 1, 2, or >2 worms | ||||
|---|---|---|---|---|
| Efficacy (%) | 0 worms | 1 worm | 2 worms | >2 worms |
| 99.95 | 88.16 | 11.07 | 0.74 | 0.03 |
| 99.5 | 28.39 | 35.61 | 22.45 | 13.55 |
| 99 | 8.32 | 20.74 | 24.90 | 46.04 |
| 98.5 | 2.6 | 8.68 | 16.09 | 72.63 |
| 98 | 0.72 | 3.04 | 8.59 | 87.65 |
Fig. 1Efficacy distribution histogram of results from parametric bootstrap analysis of efficacy data for the milbemycin oxime group as reported in Blagburn et al. [17]. Mean and 95% confidence interval for efficacy are 95.3% (93.3, 97.1)
Parametric bootstrap algorithm
| Step 1 | Denote by n1 and n2 the number of dogs in the control and treated groups in a study |
| Step 2 | Use Information criteria to identify a statistical model for control data. The possible choices include negative binomial model, Poisson model, and their variants, which take into account unobserved variability using latent effect models. |
| Step 3 | Using the fitted model obtain an estimate of the establishment rate and an estimate of the mean number of worms in the treated group. |
| Step 4 | Using the above fitted model, and including the estimate of the establishment rate, and the mean number of worms remaining in the treated group, simulate the number of worms “available for treatment” and the number of worms remaining after treatment for each dog in the study. |
| Step 5 | Using the result from Step 4, estimate the efficacy using the formula ( |
| Step 6 | Repeat Step 3 through Step 5 M times to obtain efficacies from M studies. This is typically done to yield results from 1000 or more studies. |
| Step 7 | Order the efficacies from M studies from smallest to largest and obtain the confidence interval by taking the empirical quantile of levels α/2 and (1-α/2) as the lower and upper end-point of the confidence interval. Typical choices for α are 0.95 or 0.90 |
Fig. 2Efficacy distribution histogram of results from parametric bootstrap analysis of efficacy data for the milbemycin oxime group as reported in Snyder et al. [10]. Mean and 95% confidence interval for efficacy are 99.8% (99.2, 100). Note that although one worm was seen in the biological experiment, the parametric bootstrap analysis yielded 100% efficacy more than 50% of the time