| Literature DB >> 26325426 |
Junaid Ahmad Khan1, M Mustafa2, T Hayat3, A Alsaedi4.
Abstract
This work deals with the flow and heat transfer in upper-convected Maxwell fluid above an exponentially stretching surface. Cattaneo-Christov heat flux model is employed for the formulation of the energy equation. This model can predict the effects of thermal relaxation time on the boundary layer. Similarity approach is utilized to normalize the governing boundary layer equations. Local similarity solutions are achieved by shooting approach together with fourth-fifth-order Runge-Kutta integration technique and Newton's method. Our computations reveal that fluid temperature has inverse relationship with the thermal relaxation time. Further the fluid velocity is a decreasing function of the fluid relaxation time. A comparison of Fourier's law and the Cattaneo-Christov's law is also presented. Present attempt even in the case of Newtonian fluid is not yet available in the literature.Entities:
Mesh:
Year: 2015 PMID: 26325426 PMCID: PMC4556650 DOI: 10.1371/journal.pone.0137363
Source DB: PubMed Journal: PLoS One ISSN: 1932-6203 Impact factor: 3.240
Computational results of wall temperature gradient θ’(0) for different values of parameters.
|
| Λ1 | Λ2 |
| ||
|---|---|---|---|---|---|
|
|
|
| |||
| 0.7 | 0.5 | 0 | 0.235311 | -0.395729 | -0.84128 |
| 0.5 | 0.378077 | -0.431201 | -1.14357 | ||
| 1 | 0.535309 | -0.47125 | -1.42710 | ||
| 0 | 0.5 | 0.440075 | -0.474096 | -1.22415 | |
| 0.5 | 0.378077 | -0.431201 | -1.14357 | ||
| 1 | 0.334957 | -0.402024 | -1.08247 | ||
| 1 | 0.5 | 0 | 0.333441 | -0.512599 | -1.06969 |
| 0.5 | 0.532307 | -0.570367 | -1.46365 | ||
| 1 | 0.755562 | -0.635466 | -1.82605 | ||
| 0 | 0.5 | 0.608711 | -0.622927 | -1.55096 | |
| 0.5 | 0.532307 | -0.570367 | -1.46365 | ||
| 1 | 0.480170 | -0.532685 | -1.39552 | ||
Fig 1Effect of Λ1 on f’(η).
Fig 2Effect of Pr on θ(η).
Fig 3Effect of A on θ(η).
Fig 4Effect of Λ1 on θ(η).
Fig 5Effect of Λ2 on θ(η).
Fig 6Effect of Λ1 and Λ2 on–θ’(0).
Fig 7Effect of Pr, A and Λ2 on–θ’(0).