| Literature DB >> 26116076 |
Félix Machín1, Oliver Quevedo2,3, Cristina Ramos-Pérez2, Jonay García-Luis2,4.
Abstract
Cycling events in nature start and end to restart again and again. In the cell cycle, whose purpose is to become two where there was only one, cyclin-dependent kinases (CDKs) are the beginning and, therefore, phosphatases must play a role in the ending. Since CDKs are drivers of the cell cycle and cancer cells uncontrollably divide, much attention has been put into knocking down CDK activity. However, much less is known on the consequences of interfering with the phosphatases that put an end to the cell cycle. We have addressed in recent years the consequences of transiently inactivating the only master cell cycle phosphatase in the model yeast Saccharomyces cerevisiae, Cdc14. Transient inactivation is expected to better mimic the pharmacological action of drugs. Interestingly, we have found that yeast cells tolerate badly a relatively brief inactivation of Cdc14 when cells are already committed into anaphase, the first cell cycle stage where this phosphatase plays important roles. First, we noticed that the segregation of distal regions in the chromosome arm that carries the ribosomal DNA array was irreversibly impaired, leading to an anaphase bridge (AB). Next, we found that this AB could eventually be severed by cytokinesis and led to two different types of genetically compromised daughter cells. All these previous studies were done in haploid cells. We have now recently expanded this analysis to diploid cells and used the advantage of making hybrid diploids to study chromosome rearrangements and changes in the ploidy of the surviving progeny. We have found that the consequences for the genome integrity were far more dramatic than originally envisioned.Entities:
Keywords: Anaphase bridges; Aneuploidy; Cdc14; Gross chromosomal rearrangements; Saccharomyces cerevisiae; rDNA
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Year: 2015 PMID: 26116076 PMCID: PMC4723626 DOI: 10.1007/s00294-015-0502-1
Source DB: PubMed Journal: Curr Genet ISSN: 0172-8083 Impact factor: 3.886
Fig. 1The structure and consequences of the chromosome XII right-arm anaphase bridge (cXIIr-AB) seen in cdc14-1 haploid cells. Sister chromatids for chromosome XII are depicted in light and dark blue. Centromeres are black circles and the rDNA array is in green for both sisters. The cXIIr-AB comprises centromere-to-telomere partly unzipped sister chromatids with the rDNA being the source of non-resolution. The cXIIr-AB is present at the cdc14-1 late anaphase block (upper left dumbbell cell). Release from the block leads to the breakage of the cXIIr-AB in a subpopulation of cells, leading to two daughter cells with distinct cXII content (upper center dumbbell cell). Daughter cell number one (DC1) will carry the acentric fragment of the broken sister chromatid together with the intact sister (yellow star the DSB is suitable to be repaired by BIR). Daughter cell number two (DC2) will carry the remaining centromere-containing broken sister (red star the DSB is not suitable to be repaired by BIR). DC2 will die shortly after the cXIIr-AB breakage since it lacks important genetic information present in the rDNA-to-telomere cXIIr region. Our data suggest that DC1 will survive genetically unchanged, ridding itself of the acentric fragment (lower cells)
Fig. 2Putative outcomes in diploid cells of the breakage and repair of the chromosome XII right-arm anaphase bridge (cXIIr-AB). Homologs for chromosome XII are colored in red and blue. The rDNA is in green, black circles are centromeres and yellow and red stars are one-ended DSBs once the cXIIr-AB is severed by cytokinesis. DC1 and DC2 stand for daughter cell one and two (we prefer to use this terminology since the broken pieces of cXIIr-AB seem to segregate randomly between the mother and the daughter cells). Numbered gray arrows, different mechanisms whereby daughter cells deal with the broken cXII. a Just one cXII homolog is affected by the cXIIr-AB. DC1 receives the intact sister chromatid for that homolog and the acentric piece of the second sister. DC2 gets the remaining centromere-containing fragment. DC1 might deal with the DSB by getting rid of the acentric bit (1). This would be the ideal solution as DC1 will stay unchanged; i.e., disomic and heterozygous. DC1 might also repair the one-ended DSB through BIR and become trisomic (2 or 3). If BIR takes place with the intact sister (sc-BIR), DC1 would be trisomic without LOH (2). If BIR uses the homolog as template (hc-BIR) a terminal LOH would be present in the extra cXII (3). DC2 has two choices: An hc-BIR that would result in a terminal LOH event with retention of the euploid chromosome number (4) or, else, the loss of the broken sister leading to a cXII monosomy (5). b Both homologs form a cXIIr-AB. Upon the bridge breakage, DC1 gets both intact sister chromatids and both acentric fragments. DC2 just gets the two centric fragments and thus loses essential genetic information to proliferate. DC1 can progress further if it manages to get rid of both acentric broken fragments (6). Again, this situation would be ideal since it assures an intact euploid genome. Alternatively, DC1 can get rid of just one acentric fragment and use the other one for BIR, leading to a trisomy (7). The trisomy can come with an associated LOH (7) or not (like arrow 2 in panel a) depending on whether hc-BIR or sc-BIR takes place. If there is BIR involving both acentric fragments, tetrasomy will be observed. Multiple rearrangements are possible in terms of associated terminal LOHs depending on the hc-BIR/sc-BIR combinations (8, 9 and others not depicted). c Both homologs form a cXIIr-AB. Upon the bridge breakage, each DC gets one intact sister chromatid, the entangled acentric fragment of the other sister, and the centromere-containing fragment of the broken sister from the other homolog. Since DSBs are expected at the repetitive rDNA, Single Strand Annealing (SSA) between the acentric and the centromere-containing fragments seems the straightforward solution. This would lead to a terminal LOH event with retention of the euploid chromosome number (11, 13). A similar outcome will take place if both DSBs are repaired through the canonical HR pathway. BIR-based solutions for DC1 and DC2 would lead to trisomies with or without LOH as described above (12, 14)