| Literature DB >> 200455 |
Abstract
Molybdate and copper(II)-histidine form an insoluble complex of empirical formula Cu2(His)3(MoO4)2(H2O)2ESR-spectroscopy indicated that the complex had tetragonal symmetry. IR-spectroscopy showed the presence of a carboxylate anion and suggested that the molybdate ion formed an ammonium-type salt with the nitrogens of the imidazole. The complex did not form following dissociation of the protonated imidazole (above a pH of approximately 6).Entities:
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Year: 1977 PMID: 200455 DOI: 10.1007/bf01918773
Source DB: PubMed Journal: Experientia ISSN: 0014-4754