| Literature DB >> 17316427 |
Abstract
BACKGROUND: In nature, deuterium/hydrogen ratio is approximately 1/6600, therefore one of approximately 3300 water (H2O) molecules is deuterated (HOD + D2O). In body fluids the ratio of deuterons to protons is approximately 1/15000 because of the lower ionization constant of heavy water. The probability of deuteronation rather than protonation of Asp 61 on the subunit c of F0 part of ATP synthase is also approximately 1/15000. The contribution of deuteronation to the pKa of Asp 61 is 0.35. THEORY AND DISCUSSION: In mitochondria, the release of a deuteron into the matrix side half-channel of F0 is likely to be slower than that of a proton. As another example, deuteronation may slow down electron transfer in the electron transport chain (ETC) by interfering with proton coupled electron transport reactions (PCET), and increase free radical production through the leakage of temporarily accumulated electrons at the downstream complexes.Entities:
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Year: 2007 PMID: 17316427 PMCID: PMC1808445 DOI: 10.1186/1742-4682-4-9
Source DB: PubMed Journal: Theor Biol Med Model ISSN: 1742-4682 Impact factor: 2.432
Parameters mentioned in the text and their values
| D/H | ~1/6600 [1] |
| (HOD+D2O)/H2O | ~1/3300 |
| Deuteron/Proton | ~1/15000 |
| Proton transit velocity from F0 | ~1000/s [11] |
| Half life of F0 C subunit | 40–50 hours [12] |
| Number of ATP synthases in mitochondrion | in liver mitochondria: ~15000 [22] |
Figure 1Proton/deuteron passage from F. Protons enter the cytoplasmic half-channel and reach Asp61 on subunits c. Protonated Asp61 moves into the lipid bilayer. When protonated Asp61 reaches the matrix half-channel, it is deprotonated by the stator charge of Arg210 on subunit a. A temporary stutter of the rotor is expected during the passage of deuteron. *The ratio of deuterons (D+) to protons (H+) is ~1:15000.