ENaC activity requires CFTR channel function independently of phosphorylation in sweat duct.

We previously showed that activation of the cystic fibrosis (CF) transmembrane conductance regulator (CFTR) Cl- conductance (gCFTR) supports parallel activation of amiloride-sensitive epithelial Na+ channel (ENaC) in the native human sweat duct. However, it is not clear whether phosphorylated CFTR, phosphorylated ENaC, or only Cl(-) -channel function is required for activation. We used basilaterally alpha-toxin-permeabilized human sweat ducts to test the hypothesis that ENaC activation depends only on Cl(-) -channel function and not on phosphorylation of either CFTR or ENaC. CFTR is classically activated by PKA plus millimolar ATP, but cytosolic glutamate activation of gCFTR is independent of ATP and phosphorylation. We show here that both phosphorylation-dependent (PKA) and phosphorylation-independent (glutamate) activation of CFTR Cl- channel function support gENaC activation. We tested whether cytosolic application of 5 mM ATP alone, phosphorylation by cAMP, cGMP, G-protein dependent kinases (all in the presence of 100 microM ATP), or glutamate could support ENaC activation in the absence of gCFTR. We found that none of these agonists activated gENaC by themselves when Cl- current (I(Cl-)) through CFTR was blocked by: 1) Cl- removal, 2) DIDS inhibition, 3) lowering the ATP concentration to 100 microM (instead of 5 mM required to support CFTR channel function), or 4) mutant CFTR (homozygous DeltaF508 CF ducts). However, Cl- gradients in the direction of absorption supported, while Cl- gradients in the direction of secretion prevented ENaC activation. We conclude that the interaction between CFTR and ENaC is dependent on activated I(Cl-) through CFTR in the direction of absorption (Cl- gradient from lumen to cell). But such activation of ENaC is independent of phosphorylation and ATP. However, reversing I(Cl-) through CFTR in the direction of secretion (Cl- gradient from cell to lumen) prevents ENaC activation even in the presence of I(Cl-) through CFTR.