Lanthanum(III)-catalyzed degradation of cellulose at 250 degrees C.

Lanthanum(III) chloride was found to effectively catalyze the degradation of cellulose in water at 250 degrees C. The degradation conversion of cellulose in the presence of a catalytic amount of lanthanum chloride reached 80.3% after 180 s, which corresponded to the turnover number of 83, whereas the reaction did scarcely proceed in the absence of the catalyst. The degradation products were separately quantified as water-soluble (WS), methanol-soluble (MS), methanol-insoluble (MI), and gaseous (G) products. The HPLC and GC analyses revealed that the WS materials are mainly composed of 5-hydroxymethyl-2-furaldehyde (HMF), D-glucose, and levulinic acid. Cellobiose, the disaccharide component of cellulose, was scarcely detected during the reaction.